Recent content by Sirbastian

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    How to calculate the mass of a ball based on a video

    Thanks a lot for helping me with this problem!
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    How to calculate the mass of a ball based on a video

    So when 4.9N = (m2+m1)*a1 ---> m1(t=x) = (4,9/a1) - m2 and 4.9N = (m2+m1)*a2 ---> m1(t=y) = (4,9/a2) - m2 ?
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    How to calculate the mass of a ball based on a video

    I did something wrong here (again), m2 is the mass of the falling weight m1 is the mass of the cart (+ the mass of the ball on t=x) it should be: F=m*a --> m2*g = 0.5*9.81= 4.9N Fres = m*a ---> 4.9N = (m2+m1)*a1 ---> 4.9-m2 = m1*a1 ---> (4.9-m2)/a1= m1(t=x) Fres = m*a ---> 4.9N =...
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    How to calculate the mass of a ball based on a video

    I see, so: 4.9 = (m1+m2)*1.8 = 0.9m1 --> 4.9/0.9= 5.4kg and 4.9 = (m1+m2)*3.2 = 1.6m1 --> 4.9/1.6= 3kg 5.4-3 = 1.4kg = the mass of the ball Is this the right way the solve this problem?
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    How to calculate the mass of a ball based on a video

    I want to say thank you for your support, I figured out how to do it (or at least how I think the problem is solved): m1 = xkg m2 = 0.5kg a1 = 1.8m/s2 a2 = 3.2m/22 So the amount of force from the falling weight is 0.5x9.81=4.9N F=m1 *a ---> 4.9 = x*1.8 ---> 4.9/1.8=2.7kg (before launch of...
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    How to calculate the mass of a ball based on a video

    Thanks for the reply, do you happen to know 'this equation'?
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    How to calculate the mass of a ball based on a video

    Okay, so I now know the mass of the falling weight is 0.5kg and it falls at an acceleration rate of 1.8m/s2 before ejecting the ball, and at an acceleration rate of 3.2m/s2 after the ball is ejected. How can I calculate the mass of the ball with this information?
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    How to calculate the mass of a ball based on a video

    Homework Statement I would like to know how I calculate mass of a ball based on a video. I can measure the speed of the ball at any point using Coach 3 (computer program). I know g=9.81m/s2 for the rest i don't know anything. I would like to know the way to calculate the mass of the ball in...
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