Recent content by Smile101

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    What is the acceleration of an object with given forces and weight?

    Ohhhhhh nvm! i just realized what you meant! 20/9.8= 2.0kg f=ma 10=2a therefore a= 5m/s^2 Thanks :D
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    What is the acceleration of an object with given forces and weight?

    Yea i just realized that thanks..so it would be 15+(-5) = 10 N But weight isn't only the mass, from what i know weight is equivalent to net force that's why it's measured in Newtons..that's where I'm getting confused! oh btw the answer at the back of the textbook says d) 5m/s^2
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    What is the acceleration of an object with given forces and weight?

    Hey guys, I reallly don't understand how to do this question. i'd really appreciate it if you can help me..thanks :) Homework Statement A person applies a force of 15 N [E] on an object of weight 20 N. If the force of friction has a magnitude of 5.0 N, what is the acceleration of the...
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    Optics - distance between object and image

    sorry for the late reply but, thanks a lot for your help, I really appreciated it! :)
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    Optics - distance between object and image

    so the equation is : 1/di +1/do =1/f 1/4do + 1/do = 1/20 Now I'm guessing we want to make do single... but i have to get rid of the 4 so since I'm dividing... 1/do^2 = 1/20 - 1/4
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    Optics - distance between object and image

    umm.. di=4(do) but since we don't have do we can't solve for di
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    Optics - distance between object and image

    Yes, I was thinking about that but how do I do it? Seeing as if i did m=di/do 4=di/do --but it leads me to a dead end or if i used 1/di+1/do=1/f i can only go as far as 1/di+1/do=1/20 then once again i get to a dead end!
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    Optics - distance between object and image

    hello, Homework Statement A lens has a focal length of 20 cm and a magnification of 4. How far apart are the object and the image? Homework Equations m=di(image)/do(object) 1/di + 1/do = 1/fThe Attempt at a Solution Well, I don't really know what to do, I feel like I don't have enough...
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    Newton's Law Problem: Calculating Acceleration on an Inclined Plane

    No i don't! But the modified version you gave me is right! I got 1.03! :) thank you soo much :cool:
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    Newton's Law Problem: Calculating Acceleration on an Inclined Plane

    so basically i would multiply mass with 9.81 m2 = 1(9.81) = 9.81 m1= 2(9.81) = 19.62 a= -19.62-(-9.81)sin20/3 a= 3.3m/s^2 (down) but the answer is supposed to be -1.03 m/s^2 (down)
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    Newton's Law Problem: Calculating Acceleration on an Inclined Plane

    Homework Statement A block of mass m1=2.0 kg on a frictionless inclined plane of angle 20 degrees is connected by a rope over a pulley to another block of mass m2=1.0kg. What are the magnitude and direction of the acceleration of the second block? Homework Equations...
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    How does this website read your mind.

    teheh, all the multiples of 9 are the same gifts
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    Solve Kinematics Problem: Dropped Object from Tower Height

    so i basically cross-multiplied and got 35(x+50) = 40x which then gave me 35x + 1750 = 40x 1750= 40x-35x 1750=5x 350=x sub x=350 into x/35 350/35 = 10s That doesn't make sense because the final time is supposed to be 5:40 (basically 40 minutes to add onto 5:00)
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    Solve Kinematics Problem: Dropped Object from Tower Height

    okay when i equated it i got 40t=x+50 and 35t=x now what do i do with the equations?
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