You will also want to consider heat management with that much power or you'll kill the leds very quickly. They may be efficient relative to other light sources, but most of that 100W is still dissipated as heat.
Also it would be less likely (if not completely unable) to identify and interrupt Earth leakage currents. The Earth cable is there for safety, to provide controlled path for faults.
It's not only equipment that is earthed, steel structure, reinforcing in concrete and metal plumbing are also...
Out of curiosity, what was the fan doing incorrectly for you to be troubleshooting. If it wasn't moving, a motor that doesn't get enough voltage to overcome starting friction will stall and act as a transformer with the secondary shorted, and appear to draw more current than it should.
You...
The neutral acts as a current return path in normal operation whilst the Earth acts as a fault current path in the event a malfunction causes the active conductor to come in contact with a conductive part of equipment (assuming it is bonded to an Earth conductor). It allows a large current to...
I work as a electrical engineer in building services where lighting design is a primary part of my job. Sophiecentaur is correct, a poorly illuminated sign will be noticeably bad.
I stand by my suggestion above, find a local lighting supplier (commercial not residential) and get some...
There is software to simulate lighting installations that is free, It is called Dialux. Generally you need to pick a fitting and get the photometry file which is essentially a polar plot of luminous intensity.
You may be able to palm the calculation part of the problem off onto a lighting...
I'm afraid its not as simple as you may be imagining, a resistor in series or parallel with the motor won't have the effect you desire without the resistor being completely impractical and consuming just as much power as the motor. The most common way to control the speed of a DC motor is...
Apparently the wolfgang spindle is excelent for PCBs with narrow traces, there are some videos on youtude demonstrating. Can't say about the zenbot however.
I use circulon ceramic titanium non stick pans, they don't have teflon in them and are completely safe from what I have found. They also cook very well.
Under fault conditions it is the impedance of the fault path and the impedance of the source that determine the magnitude of the current (assuming bolted fault). A closed ring has 2 paths from source to fault in parallel, therefore the impedance is less. Perhaps 'lines' wasn't the best word to...
I'm currently looking into this myself. I'm starting to lean towards a zenbot router with a wolfgang engineering spindle. Comments I have read on forums around the web seem to be favourable to these products. I think you could expect to pay around $1500 for the lot however, which is still a...
Going from an open ring to a closed ring can be difficult. The fault currents in the lines are increased, basically doubled as the 2 paths are in parallel. It also complicates the protection settings. I have had limited experience with HV, but from what I can gather it is only done in...
For simpicity we don't refer to the sinusoidal aspect of the system because we are assuming a contstant frequency. The voltage on each phase is described by the following functions:
P1 = V sin(ft + 0)
P2 = V sin(ft + 120)
P3 = V sin(ft - 120)
Where V is the peak Voltage, f is the...
Sorry, I said addition earlier, it should be subtraction.
It's best to look at one of the phases as being a reference, say 0 volts, then the other phase is the vector difference of the 2 phases. (yes this is superposition)
Lets say,
100V 0\phi and 100V 120\phi
[Isert maths here]...
In short, the main panel ground rod provides a reference voltage for the system, and a controlled path for current under fault conditions.
The way I understand your description would not work. The current that powers the light bulb you speak of still needs to make it's way back to the...