Homework Statement
So this is the question
|x-1|+|x-2|>1
Homework Equations
N/A
The Attempt at a Solution
I tried it, the solution seems right, but i don't know if my approach is correct.
I think i got it now:, Also when i take a square root of a number, isn't that i should take the positive and negative root?. I understand for \sqrt{x^2}=x, because its basically \abs{x}
Just to make it simple to solve for now, i am not going to look at case a=0 (only for now)
so i tired to do this:
Again my solution is wrong, i am now covering the entire number line (-inf,+inf), i feel like i am messing up basic algebra. Please help
Homework Statement
The problem is:
for all 0≤a≤1
so i need to find the domain
Homework Equations
N/A
The Attempt at a Solution
I tried it like this:
yet my solution is wrong,i am not so sure why.
wolfram gives me this;
But when I try to do the same thing for |x-1|*|x+2|=3 which is:
|x-1|*|x+2|=3
|x-1|=3 or |x+2|=3
x-1=3 or x+2=3
x=4 or x=1
But this solution does not make sense...
please help, Thanks!
Homework Statement
find all the numbers x for which |x-1|*|x+1|=0
Homework Equations
The Attempt at a Solution
|x-1|*|x+1|=0
|x-1|=0 or |x+1|=0
x-1=0 or x+1=0
x=1 or x=-1
but I think there's a flaw some in my attempt solution...or the whole thing is a flaw..
any help...
Hi, I only used Khan Academy videos for Linear Algebra (even though i knew about them long before) because my prof puts up so we could see it before our linear algebra lecture. The videos are great. I am surprised you guys haven't heard of Khan Academy. cheers!
p.s I'm sorry that the answer to...
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