Recent content by someGorilla

There's a different issue at work here. Normally the light emitted by a computer screen is not a linear function of the RGB values. Try setting your screen's gamma correction to 1. You will see how your two pictures have more or less the same brightness.

Have fun

Yes, it's uncountable. And yet you're right on this: Look at this. The set of non normal irrationals is uncountable but has Lebesgue measure zero. If you choose a random irrational (or a random real, for that matter) you have 0% chance of landing on a non normal number, that is you have 100%...

Although this is probably true, it's also true for the majority of irrational numbers, so why concentrate on pi when sqrt(12345) is equally likely to contain Hamlet in ascii code?

Oh, now I see. You're right. Still, you need uncountably many representatives because you have uncountably many equivalence classes, no shortcut around that.

Without stepping into the discussion (which I find interesting but a bit empty if we don't have a shared definition of what we mean by "multitasking")... can anybody steer me to the reports/articles/whatever of the neurological experiments that supposedly have been done about this? I've heard...

Oh, by the way, why cling to this wimpy version of the paradox? Instead of real numbers, you might have anything inside the boxes. Box #3 might contain π^{2}, #5 might contain a Mexican sombrero, #200 might contain Borges' library, and #201 a complete copy of the whole set of boxes. And still...

I don't get what you mean... what are finitely many sets of representatives? What is a set of representatives? True, but this has no importance. There's one representative per class anyways. Since there are uncountably many equivalence classes...

No. They must all use the same representative. That's why they need to concoct a strategy before the game starts. They must agree that for all sequences of a certain group the representative is, for example, 4, 6, 0, 0, 9, 8, 4, 7, 3, 5... In your case, with this representative all prisoners...

Wow. This had me dumbfounded for a good while. It reminded me of a similar one I read some time ago, and that time I wasn't able to figure out how the heck it could work. There's an infinite (countable) number of prisoners awaiting to be executed, standing in a queue. The hangman sets a white or...

$$\sum_{m=3}^{9}\frac{(m-1)(m-2)}{2}·\frac{m(m-1)}{2}=2142$$ Took me more to typeset it than to figure it out :biggrin:

No. How could H=0° and H=360° give the same RGB values if it were linear? How can you represent white with wavelength and intensity? Or even magenta?

What if the three locations are equidistant from you but with different pressures? Our almost equidistant and with different pressures? You can get VERY strange results. Edit: oops MisterX beat me to it

Strings cannot form knots in 4 dimensions. (or only trivial knots) But this got me thinking that 2d surfaces can form "knots" in 4 dimensions. Are these, too, called knots in topology? By tom.stoer's definition for example the Klein bottle would be a knot in 4d, though not in any superior...

Having read till the beginning of the second page (yep I know I shouldn't have :biggrin: ) I understand the question to be "how can the two paths be diverging in one frame and converging in the other?" It's a trick question! I hand't got it at first since it's not so strange that two lines...