I have re-done this problem, and indeed your "most simplified" :smile: is more accurate:
I also found this old magazine article about liming lakes:
Cheers!
I calculated it and found that is approximately 610Kg needed of CaCO3 to bring the lake pH to a neutral level.
Is my calculation right 1st :)?
Then if this is right, 610kg of CaCO3 is not that much in a matter of cost or weight to help the bio-life of the lake. I'm wondering if we are applying...
Thanks Borek for your reply.
I'm still confused though; how water can be evaporated at 25°C then heated, Is it by lowering the pressure? And what the compression work is needed for?
According to the Vaporization Heat table, the heat needed for 1 mol of H2O to evaporate at 100°C is 40.7KJ and 44.0KJ/mol is needed to evaporate H2O at 25°C. Thus 44.0-40.7=3.7KJ is the energy needed to heat H2O to 100°C from 25°C. However, according to the heat capacity of H2O, 3.7KJ will only...