Recent content by stripedcat

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    Two Blocks attached by a string, on an incline

    Woops, sorry. O_O I missed that. 3 * (9.8 + 6.03) = 47.49 I don't know what the summation F means. Sum of forces on the block? I usually have practice problems so I can play with them until I figure out how to do them, no such luck on this one.
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    Two Blocks attached by a string, on an incline

    I'm sorry, but... What? The force that acts on each block is gravity, 9.8 * sin theta. That's how I got acceleration. T = m(g+a)? But is that mA or mB?
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    Two Blocks attached by a string, on an incline

    Homework Statement In the diagram mA is equal to 3.00 kg and mB is equal to 1.07 kg. The angle of the inclined plane is 38.0° (a) Find Acceleration: 6.03 m/s^2 (got this part) (b) Find the tension Tb in the connecting string: Not sure Homework Equations (a) a = (F/mA + mB) (b) t =...
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    Projectile Motion: Angle of Impact

    Oooh, had the wrong Vx/Vy, or the wrong Vy rather. That was the problem. Thanks.
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    Projectile Motion: Angle of Impact

    Homework Statement A ball is thrown from a bridge 200 m high with an initial velocity of 34.4 m/s at an angle of 54° above the horizontal. Homework Equations I'm not sure... arctan Vx/Vy = x? I really don't know. The Attempt at a Solution (a) How high above the throwing height does...
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    MHB Partial Fraction Question: Simplifying ln(2) and ln(3) to ln(8/3) in 8/5 form

    Sooo 24/5 ln(2) - 8/5 ln(3) (24/5)/(8/5)=3 8/5 (3ln(2) - ln(3)) 2^3 = 8 ln(8)-ln(3) 8/5 ln(8/3) Ace.
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    MHB Partial Fraction Question: Simplifying ln(2) and ln(3) to ln(8/3) in 8/5 form

    Without being too concerned how we got there. The answer to a partial fraction question a friend and I are doing is 24/5 ln(2) - 8/5ln(3) The system does not accept this answer however, it wants the simplified form 8/5 ln (8/3) We're not sure how to get that form. More specifically 8/5...
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    MHB Studying for a Test with Variable Answers

    Yeah but if anything ELSE changes... say, the terms of integration, or exponents are 4s instead of 2s... I could change them and try to solve myself, but I'd have no way to know if I was right unless wolfram or something confirms it. The advantage here is the ability to do slightly different...
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    MHB Studying for a Test with Variable Answers

    Funny you should ask because I just got that one. Literally. I know because after doing about 10 practice problems, you see the trend. It's always the number in front of the sin^2x, times pi, over 16. In that instance its just 1pi/16 which naturally becomes pi/16. Even if you had no idea...
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    MHB Studying for a Test with Variable Answers

    This technically might not belong here, mods, put it in it's proper place if not. So I'm studying for a test on Monday. Not a big deal, we use webassign, you may commence with the horrified gasps and groans, I know. So here's my odd little situation. I get a problem like this one Integral...
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    MHB Arc Length and Rotation, Please Explain this problem

    Sort of amusing coinsidence then that 4^3 * 36 is 1 shy of what I was looking for... Heh. But thank you!
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    MHB Arc Length and Rotation, Please Explain this problem

    Indeed. Here it is. Can somebody explain how to get the new terms of integration? I understand the rest of it. I know where everything else came from, I don't know how they altered the terms of integration to 1 to 2305 And if anyone can delete that image above that would be helpful. EDIT...
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    MHB Arc Length and Rotation, Please Explain this problem

    EDIT: Okay now that the admin has cleaned up my mess, please scroll down to see the correct image and the question on the 3rd post in this thread.
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    MHB Understanding Partial Fraction Decomposition in Integrals

    Anything is possible. Had a problem last week with other trig related inputs. The examples always showed 'sinx', but if you put in 'sinx' for your answer, it counted it wrong... But only sometimes. But it always counted sin(x) right.
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    MHB Understanding Partial Fraction Decomposition in Integrals

    Scratch all that noise. My answer was 'wrong', and yes, there was a uh... 'not so kind' email over this. Typing out tan^-1 vs using the system to make a 'tan^-1( ) You tell me if you can tell the difference, maybe I just don't see it.
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