Every time I have taken moments before I have been able to solve for the required unknown regardless of what point I choose, unless there is more than 1 unknown! However I tried taking moments from the far left point load of 97.5 this time and I get the wrong answer. I don't understand why...
Ok, thanks guys. Assuming it's a load makes sens I suppose. Also I have a lot of questions around this level in the coming weeks, is this the correct forum for that? Thanks.
At any point between A and C the point load is negative (downwards), in the shear force diagram: positive is upwards, so this slope is negative. The equation says the slope should be positive. Is this something to do with shear force sign convention?
I suppose they can't gain the vertical velocity without a change in their height either, so I was wrong with what I said. Even if its just an almost infinitesimal amount of distance traveled upwards..
Thanks!
If we use the eq. before they jump then we have 24.8 for horizontal and magnitude of velocity, Then as they leave the ramp I can solve for 25 magnitude.
I still have a slight problem with the general model though. If we use the same equation for when they start to jump, but before...
https://ibb.co/jG6n0jZ
The 15 is fine as this is clearly his overall magnitude but then v2 is equated to the horizontal velocity rather than the magnitude.
In the books workings it says they are resolving vertically upwards and clarifies that it is indeed the reaction at the hinge:
https://postimg.cc/Wtn5VyxJ
https://postimg.cc/JtP2h113
I think I may have forgotten some more basic elements of tension and normal reactions. I do not understand why the vertical component of the normal reaction =Tsin60-15g
Because Tsin60-15g is negative when resolving upwards, i would have thought this meant that the...