hello everyone,
I have a problem, if anyone can get me started. Thanks
I have to show this equality knowing that a and b are positive and they do not euqal 0:
(a^{2}+a^{\frac{4}{3}}b^{\frac{2}{3}})^{\frac{1}{2}} + (b^{2}+a^{\frac{2}{3}}b^{\frac{4}{3}})^{\frac{1}{2}}...
Hey everyone
I had difficulties while solving this problem in probability.
We have 4 similar boxes, and 20 similar balls.
How many possible ways we can put those balls on those boxes, knowing that
-the first box contains 3 balls
- the second box contains 4 balls
- the third box contains...
okay, here is what i got to:
-2sin(B/2-C/2)cos(B/2+C/2)+2sin(B/2)cos(B/2)+2sin(C/2)cos(C/2)
okay, i might replace -2sin(B/2-C/2)cos(B/2+C/2) by -sinB-sinV but that s not going to help me any better!
and how can this above, be equal to 4cos(A/2)sin(B/2)sin(C/2)
PS: as u might have noticed...
okay i was tryin that durin the past 20min, and i didnt get to what i want, however i got to know that tan(A/2)=(1-cos(b))/sin(b) and even with this, i didnt get closer to what i want. help would be apprciated :)
hmmm i see, thanks :)
i also have to show that, in a triangle <-> A+B+C=pi ;
sinB+sinC-sinA=4cos(A/2)sin(B/2)sin(C/2)
if someone can just give a hint r something to start with, because this one is really confusing me! :confused:
thanks!
ok here,
i simply expanded the sin(b-c) and sin(c-a) and sin(a-b)
and finally i got:
sin(a)*(sin(b)cos(c)-sin(c)cos(b))+sin(b)*(sin(c)cos(a)-sin(a)cos(c))+sin(c)*(sin(a)cos(b)-sin(b)cos(a))
and i still expand that to get...
hello
i have to simplify this :
sin(a)sin(b-c) + sin(b)sin(c-a) + sin(c)sin(a-b)
I did simplify it and I got it equal to zero. But my problem is, I did too many steps in order to do that. Does anyone have a shorter way to simplify that ??
thx!
okay!
so, i had an exercice that say:
it's 11:12am, what s the angle between the two switches?
the problem here that stopped me from solvin that is when its like 11:12, the first switch, is not at 11am but it s slightly after that! :confused: i am confused! :frown:
any help is apprecied
Hello,
I have to write {\it sina}+{\it sinb}+\sin \left( a+b \right) as a product.
Here is what I began with, then I got stuck...
2\,\sin \left( (a+b)/2 \right) \cos \left( (a-b)/2 \right) +{\it sina}\,{\it cosb}+{\it cosa}\,{\it sinb}
Anyone please can help me out, that would be...