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terminal.velo
Recent content by terminal.velo
T
Max/Min f subject to g: Lagrange Multipliers
2x(1/4 - λ) = 0 2y(1/9 - λ) = 0 2z(1 - λ) = 0 EDIT: I'm in a bit of a funk, apologies! (lectures from 8am 'til 3pm)
terminal.velo
Post #7
Apr 10, 2013
Forum:
Calculus and Beyond Homework Help
T
Max/Min f subject to g: Lagrange Multipliers
All 3 derivates of L (Lx, Ly, Lz) have to equal zero, to find the λ, then the x/y/z for critical points of f(x,y,z) Lx = 2/4*x - λ*x*2 = 0 Ly = 2/9*y - λ*2*y = 0 Lz = 2*z - λ*2*z = 0
terminal.velo
Post #5
Apr 10, 2013
Forum:
Calculus and Beyond Homework Help
T
Max/Min f subject to g: Lagrange Multipliers
I don't know, the lecturer told us to solve the rest of the problem at home.
terminal.velo
Post #3
Apr 10, 2013
Forum:
Calculus and Beyond Homework Help
T
Max/Min f subject to g: Lagrange Multipliers
Homework Statement Find max/min of f subject to constraint: x^2+y^2+z^1 = 1 Homework Equations f(x,y,z) = 1/4*x^2 + 1/9*y^2 + z^2 g(x,y,z) = x^2 + y^2 + z^2 - 1 The Attempt at a Solution L = 1/4*x^2 + 1/9*y^2 + z^2 - λ(x^2 + y^2 + z^2 - 1) Lx = 2/4*x - λ*x*2 Ly = 2/9*y -...
terminal.velo
Thread
Apr 10, 2013
Lagrange
Lagrange multipliers
Replies: 7
Forum:
Calculus and Beyond Homework Help
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