Thanks for your response.
So that means the handle assembly is fastened to the exterior stationary pole in some way correct?
I need to make a system like this where the threaded rods extends but want it to rotate through 360deg (preferably only once) as it extends. is there a way to achieve...
Firstly, am struggling to wrap my head around exactly how the mechanism for a traditional 'hills hoist' (as seen below) clothesline functions.
The handle can be turned in order to raise the clotheslines but from my googling, the mechanism is different to what I was expecting.
Would be...
Okay so now I have (-Va/8)-(Va/6)-(Va/4)=(-4/6)-(12/4)
Which gives Va as 6.77V and a corresponding i of -1.31A
The negative current means i is flowing the opposite way to what I have marked (towards top of diagram)
Oh of course! brain fade..
I calculated Va as 12.57V so therefore i has a value of (12.57-12)/4 = .143A
Thanks for your help!
I will attempt to solve the thevenins problem by myself but will post later if I can't get there
Okay cool, so if i1+i2+i=0
Then (-Va/8)+((Va-4)/6)+((Va-12)/4)=0
But I can't work out how to solve for Va from here, is there another equation I am meant to be using to solve with substitution?
This shows what I have attempted, I think where I am going wrong is the way I am doing the voltage differences but I am really struggling to understand specifically where I am going wrong
I understand that part, however I thought that the equations I had put in my attempted solution were in terms of voltage differences and the three voltages? I thought that the way the circuit was laid out, all three voltage differences would be dependant on Va?
Homework Statement
Am having trouble solving the initial part of this problem, I think I am being confused by the dual voltage sources.
2. Homework Equations
I=V/R ΣI at a node =0
The Attempt at a Solution
V3/R3 - (V1/R1+V2/R2) = 0
V3=12-VA
V1=4-VA
V2=VA-4
However this must be incorrect...