Okay, this is the first answer that seems to make sense to me (Bernoulli's principle doesn't apply since the speeds aren't constant). But I am still hung up on why in the original example, P_2=P_1.
So according to Bernoulli's equation as I understand it, v_1 is the instantaneous speed of the fluid at point 1, and likewise for v_2 at point 2.
I understand what should happen if I just use Newton's laws and forget about fluid dynamics. As you said, in either example, the speed of the fluid...
Neither of these answers seems to resolve the paradox I am getting. Here are diagrams of two other situations where the Bernoulli equation should have the same form as before: v_2^2-v_1^2=2gh+\frac{2(P_1-P_2)}{\rho}. The first is simply a U-shaped tube with water in it at different heights (it's...
I know how to solve the original problem is to set P_2 to atmospheric pressure and then the solution is just v_2=\sqrt{2gh}. What I am hung up on is why should P_2=P_1?
So if I put a small test swatch of area just outside the can, it will of course experience a force due to atmospheric...
First, this is is not a homework problem, per se, but it is a conceptual difficulty I am having with my physics 1 course, in which we are studying fluid mechanics (moderators please move this post if there is a more appropriate subforum).
Homework Statement
I was going over the derivation...