Recent content by tre2k3

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I am going over this example 0.5 kg of air undergoes a Carnot cycle with η = 0.5. Given the initial pressure p1 = 700 kPa, initial volume V1 = 0.12 m3 and heat transfer during the isothermal expansion process Q12 = 40 kJ, Find the highest and the lowest temperatures in the...

Heres my given problem: Gauge Length = 2 in. Area = 0.5 in^2 The specimen yields under a load of 32,000 lb The corresponding gauge length is 2.0083 (the 0.2 yield point) Max load = 60,000 lb @ gage length = 2.60 in I need to determine the yield strength, modulus of elasticity, and...

yeah, lb/ft had me going cause i needed to cancel out some other units so I just did a conversion and I got the right answer

im not getting the correct answer for B. I did it by just the numbers they gave me and tried to do it by converting to regular units such as N/M or m/s^2

TA Chuck Margraves spends his spare time bungee jumping off the Henley Street bridge. He has a 14 ft long bungee cord (unstretched) that has a spring stiffness of 22 lb/ft. To test his bungee, Chuck ties the bungee cord to the bridge railing, ties the other end to an unnamed EF professor...

since i don't know the height in the equation, how do I relate that to the poisition

One more thing. I having trouble understandin this one. "If instead of there being no losses, there is gravel on the runaway truck ramp that provides a constant force of 2620 pounds in the opposite direction of motion. What distance does the truck travel along the runaway truck ramp in this...

i got it :bugeye: :smile: :cool:

nevermind about the length of the ramp, that was justg the distance til the truck gets to the ramp.

I converted my initial KE from ft-lbs to J and had that = to my inital KE. So i converted 6010000 ft-lb to J by multiplying by 1.36J/ft-lb which = to 8200000 I use the equation KE1+PE1+Work=KE2+PE2+Eloss Since no energy was loss I canceled that out. I canceled out PE1 because the height was...

6010000 ft*lbs KE i got from dividing 8200000J by 1.36J. They just gave me some conversion factors to work with. I am thinking i should use F*Scos(theta) which equals work.

Since I kind of new to this concept, how exactly do I go about measuring the bottom of the ramp. Do I set the value of h to 0 in mgh. Does the length of the ramp matter at all?

you can delete this post

yeah, I think the units will get me. I had to convert from ton and mph to kg and m/s and divide that by 1.36 J just to get ft-lb.