I have an object that is going up the plane at 25 degrees to the right. It is going at 15 m/s. I drew a free body diagram of the object. I have a P force at 15 m/ s going up the direction at 25 degrees. I also have friction force going in the opposite direction of 0.25 * N.
ay = -9.8. Vy = -9.8 + v0*Sin0. y = -4.9*t^2 + v0*t*Sin0. By using formula of y, my solution was -4.9(10s)^2 + (10m/s)(10s)Sin0. I assumed that y was equal to 0. Since -4.9 is m/s^2 the answer would be -490m + 100m*Sin0. Therefore I assumeed Sin0 = 490/100.
On my Engineering Mechanics Dynamics Book I am working on a problem that states: "A motorcycle travels along a straight road between two points at a mean speed of 30 m/s. It returns at a mean speed of 15 m/s. What is the mean speed for the round trip." The correct answer is 20 m/s. On working on...