A tether ball leans against the post to which it is attached (Fig. 5-40). If the string to which the ball is attached is 2.00 m long, the ball has a radius of 0.300 m, and the ball has a mass of 0.400 kg, what are the tension in the rope and the force the pole exerts on the ball? Neglect any...
So I have a point A on a graph with x and y axes. From the origin, the point is 3r to the right, and 1r up. I'm to find the Moment of Inertia along the x, y, and z axes. I've found the x and y moments, but not the z and I'm not really sure on how. I'm not getting any ideas from the graph...
Hey I'm sorry I'm not a physics genius like you are cepheid. I appreciate the help but I can do without the snide comments. Anyway, I was leaning toward differentiating and I tried it and came out with a wrong answer. Computations were probably inaccurate though.
A fan blade rotates with angular velocity given by omega_z(t) = gamma - Beta(t)^2 .
Calculate the angular acceleration as a function of time.
I don't even know where to begin and my book is all but useless. Any ideas?
A wagon wheel is constructed as shown in the figure. The radius of the wheel is 0.300 m, and the rim has mass 1.36kg . Each of the eight spokes, that lie along a diameter and are 0.300 m long, has mass 0.270kg .
What is the moment of inertia?
Wouldn't it just be the sum of the masses...
Bullet is fired at a block resting on a table. The velocity of the bullet is 390 m/s and has a mass of .007kg. The mass of the block is .850kg. The bullets penetrates the block and exits it with a velocity of 130 m/s causing the block to slide a distance of .410 m.
What is the coefficient...
The key is to find the Initial and Final centers of mass.
Initial: Woman's CoM = 1m , Canoe's CoM = 2.5...What's the CoM of the entire system?
Final: Woman's CoM = 4m , canoe's CoM = 2.5...CoM of System?
Final CoM - Initial CoM = your answer
This is what I've done so far
Work-energy theorem: E_f-E_i=W_fr:
0-(1/2)*m*v^2=- mu*m*g*2*x
x = .5v^2 / (2g(mu)) Max compression of spring
W=-mu*m*g*x
E_i=(1/2)*m*v^2 )
E_f=(1/2)*k*x^2
Work-energy theorem:
(1/2)*k*x^2-(1/2)*m*v^2=-mu*m*g*x
Plugged into x and...
An object of mass m is traveling on a horizontal surface. There is a coefficient of kinetic friction, mu , between the object and the surface. The object has speed v when it reaches x=0 and encounters a spring. The object compresses the spring, stops, and then recoils and travels in the opposite...