I put them both positive first and then i changed it, i think I am thinking in the one dimension so I am seeing the second photon in negative y quadrant, but looking in the x,y,z plane i think it would be positive, the signs r what i am most unsure of, is the rest correct?
they are my initial vectors that i came up with, but i changed theta 2 into 180 because it is in the rest frame and also expressed E2 in E1 since in the rest frame they are equal but opposite, am i completely off the track here? or am i getting close... :S
oo ok can u check if my new vectors are correct please?
photon 1= (E1 sina, E1 cos a , 0 , E1)
Photon 2= (-E2 sinθ2 , -E2 cos θ2 , 0 , E2) = (0,E1,0,-E1)
using E1+E2=0 and since they are photons E=p
are these right, especially the signs?
O ok so the equation would be
I=Iosin^2((π/λ)asinθ-∅)/ ((π/λ)asinθ-∅)^2
it gives a hint to consider the intensity halfway between the peaks of the two images so i did
((π/λ)asin(θ-∅)) = ∏/2
but where do i put the intensity change of 0.2% to get (θ-∅) = 0.00015?
Homework Statement
One mole of an ideal monatomic gas initially at volume Vi and temperature 1000k expands to a final volume Cvi in three reversible steps: 1) isothermal expansion from Vi to aVi, 2) adiabatic expansion from aVi to bVi and 3) isothermal expansion from bVi to Cvi
In terms...
Homework Statement
Model the pupil of the eye using a single slit. If the eye is able to notice changes in intensity of 20% show that it can distinguish two objects separated by an angle of 0.00015 radians if =500nm and diameter=4mm.
Homework Equations
I=Iosin^2((π/λ)asinθ)/...
ok so if i didn't sub in the values my vectors would be in the rest frame:
Photon 1 = (E1 sina, E1 cos a , 0 , E1)
Photon 2 = (-E2 sinθ , -E2 cos θ , 0 , E2)
a and θ is what they've asked for in the question, so to get the lab frame i use the lorentz transformation but i then have to...
Homework Statement
Two loudspeakers, at the same height are 2m apart and in phase with each other.Both emit 705Hz sound waves into a room. A listener stands 5m in front of the loudspeakers and 2m to one side of the centre.
a) Is the interference pattern at this point...
Hi Simon
Sorry the mass is actually 100kg! not 1000kg so the energy would be 2943J but I am not sure if I should divide by 20 to get 147.15J per cycle before I plug it into the equation, should I plug in 2943J or 147.15J as the work done or should i divide by 20 after?