Recent content by vince_lu

  1. V

    What is the Applied Force Needed to Accelerate a Curling Stone on Ice?

    I think I'm getting it better now. Would it then be: 0.080[back] x 19kg x 9.8 + (19kg)(1.8m/s^2) F=49N[forward]
  2. V

    What is the Applied Force Needed to Accelerate a Curling Stone on Ice?

    Newton's Second law is an object will accelerate only wher there is a net external force acting So far I figured out: m=19kg a(acceleration)=1.8m/s^2[forward] (u)coefficient of Fk=0.080[back] F(applied force)=? Idon't know how to setup the equation
  3. V

    What is the Applied Force Needed to Accelerate a Curling Stone on Ice?

    a curler exerts a force forward on a 19kg curling stone and gives it an acceleration of 1.8m/s(squared) [forward]. the coefficient of kinetic friction of the ice on the curling stone is 0.080 [back]. calculate the value of the applied force. thank you in advanced
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