Recent content by w0lfshad3

This is a conditional probability actually. ABCDE;E AAA;EEE was calculated as 4/45 experiment sais 0.0659658333 3/45 is very close: 0.0(6) Anyone knows how to calculate this probability properly?

Actually the point is only the number matchings on the lottery using just 3 player numbers. This is a conditional probability problem. I experimented on matching all numbers between ABCD;EE and ABCD;EE Hypothetic (calculated) probability: 1/1260 Real probability: ~1.75/1260...

What is the probability of the player matching exactly 3 numbers from a 10 number lottery (0...9) w/o repetition, given the conditions: - player and lottery pick 6 numbers; - player always has a repeated number; - lottery always has a repeated number. for example: 123455 123455 Here there's...

Well, that wiki bit was inspiring, even if it that formula I posted is wrong for this problem because it's for no replacement balls. I should've posted this one instead perhaps: The general formula for B matching balls in a N choose K lottery with one bonus ball from a separate pool of P...

I didn't calculate the probability right in the last part, it's 5040/56700, which is 0.0(8), or 4/45. Explanation: Where did I go wrong: " C(5,2)C(10-5,0)/C(10,2)=10/45 for the hipergeometric part, then, because the repeated unit can only be one of those first two that matched, it has 2/10...

Problem solved experimentally, but need to find an elegant combinatorial formula for approximating the result instead. Also need verification of the solution below. Problem data is: sample space is numbers from 0 to 9 lottery picks 6 numbers, but only 2 are distinct (Example: 111444)...

Have an example: 123455 111555 the sample space is 0..9 row 1 can pick 6 numbers out of which 2 are repeated row 2 can pick 6 numbers out of which 3 by 3 are repeated I want to know what is the real probability that row 1 will match with 2 distinct numbers numbers row 2, and a repeated number...