Homework Statement
Find the set of points where the gradient of f is parallel to u =(1,1) for
f(x,y)=x2 + y3 + 2xyHomework Equations
the gradient of f(x,y)=((partial derivative of f wrt x), (partial derivative of f wrt y))
u=grad f
The Attempt at a Solution
fx = 2x+2y
fy = 3y+2x
1=2x+2y...
So the I found that the voltage on C1 is 3 V and since it is in parallel with C2, then C2 has 3V as well. So that means that 3V remains to be used, which is then split between C3 and C4, having Q4 being 1.5V*15μF which would come out to be 22.5 μC.
I actually want to understand it fully...
That us a weird way of thinking to me because we have yet to learn about optional directions and whatnot. I was not sure how to go about combining c3 and c4. Thanks a lot.
Now concerning the actual calulation. Would I have to find The voltage that would reach c4 or will the full 9 volts reach...
I understand how I am wrong on the last bits but how am I wrong on the Ceq? I have gone through it multiple times and continue to come up with 5 as the overall capacitance.
C123=1/(1/30 + 1/15 + 1/30)
C1234=1/(1/C123 + 1/15)
I get 5.
If I am wrong then I do not quite understand how...
Wow, that was very helpful. I was fiddling with some other solutions and one was in that direction but when I hit the remaining voltage for C1 and C2 for 1V, I discarded it because I thought it was wrong.
So I have 1 V to split between C1 and C2
so C1 has a charge of 4 μC and C2 has a charge...
Homework Statement
Using the figure, calculate the charge on capacitor 4.
Homework Equations
Q=C_{eq}V
V=Q/C
The Attempt at a Solution
The C_{eq} for the entire system is 5\muF
C_{14} = 10\muF
Since C1 and C4 are in a series, wouldn't they receive the same 9 volts? If so...
Homework Statement
Calculate the charge on and the potential difference across each capacitor
Homework Equations
C|| = C1+C2+C3...
C(Series) [(1/C1)+(1/C2)+(1/C3)+...]^{-1}
Q=CV
V=Q/C
The Attempt at a Solution
I already know that C_{123} = 16/9 \muF
I also already know that...
Homework Statement
A car moving at constant acceleration covers the distance between two points 58m apart in 6.2 seconds. its speed as it passes the second point is 54 km/hr. what is the speed at the first point? at what prior distance from the first point was the car at rest?Homework Equations...