Recent content by Yubsicle

Thanks to everyone for taking the time to help.

Alright, I used the trig identity ##\cos(\theta + \pi) = -\cos(\theta)## and got ##\phi = \pi \:\mathrm{rad}## and ##A = 0.32\:\mathrm{m}## (rounded to 2 sig figs), as well as ##\omega = 6.9\:\mathrm{rad/s} , T = 0.91\:\mathrm{s}, f = 1.1\:\mathrm{Hz}##. Is my use of trig identities, and the...

I think I get it now. Plugging ##t = 0## into the equation given by the problem gives ##v = 0##, so ##\sin(\omega t+ \phi) = 0## if ##\phi = 0## and so ##x = A \cos\omega t## . However, I still get ##A = -0.3188##. Do I just take the absolute value, since the cosine function has the same...

Oh, it looks like I misread my textbook. Apparently ##x = A \cos(\omega t - \frac{\pi}{2})## only works if ##x = 0## when ##t = 0##, and otherwise it's ##x = A \cos(\omega t + \phi)##. So I was wrong in assuming that C = 0. That brings me to $$(-0.3188 \mathrm{m})\cos...

Homework Statement A simple harmonic oscillator, with oscillations in the x direction, has velocity given by: $$v_{x} = (2.2 \frac {\mathrm{m}} {\mathrm{s}}) \sin [(6.9 \frac {\mathrm{rad}} {\mathrm{s}}) t]$$. Find the values of ##\omega , A, f , T ,## and ##\phi## Homework Equations $$v_{x} =...