Why objects at lagrangian points 4 and 5 are stable?

In summary, objects at lagrangian points 4 and 5 are stable because the mass ratio between the primary and secondary masses is greater than around 22:1.
  • #1
magnetar
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why objects at lagrangian points 4 and 5 are stable?

Thank you in advance!
 
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  • #2
Is the http://en.wikipedia.org/wiki/Lagrangian_point" explanation ("[w]hen a body at these points is perturbed, it moves away from the point, but the Coriolis effect bends the object's path into a stable, kidney bean‐shaped orbit around the point") insufficient for a particular reason?
 
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  • #3
magnetar said:
why objects at lagrangian points 4 and 5 are stable?

Thank you in advance!

Small masses at the L4 and L5 points are stable if and only if the mass ratio between the primary and secondary is greater than around 22:1. (I don't recall the exact figure offhand).

Demonstrating this using calculus is a rather lengthly calculation, involving finding the equations of motion of the small mass, linearizing the resulting differential equations, and showing that these linearized differential equations don't have exponentially growing solutions.

If you have the necessary background in calculus and the interest, I could provide a few links.
 
  • #4
pervect said:
Small masses at the L4 and L5 points are stable if and only if the mass ratio between the primary and secondary is greater than around 22:1. (I don't recall the exact figure offhand)...

Big masses are stable there too. To get the exact figure you would need to specify how the secondary masses are divided. For example, you could have a star, a planet, and a massless test particle in the Planet's L4 or 5 point. Or you could have a star, and 2 equal-massed planets spaced 60 degrees apart, or any combination inbetween. It doesn't make a huge difference, changing by something like (my guesses) 22:1 to 23:1 between these two extreme conditions.

Here's the results of a Gravity Simulator simulation I performed trying to find out the mass ratio between the star and two combined equal-mass planets. The first column is is the mass ratio ((Planet1 mass + Planet2 mass) / star mass). The 2nd column is how many years this trojan configuration is stable. In this example, the equally massive planets are 1 AU away from a 1 solar mass star.

The interesting part is that it is unstable for all values ratios greater than or equal to 0.041, then it becomes stable for a small range of ratios from 0.04 to 0.031, then becomes unstable again for a small range of ratios from 0.03 to 0.0286, then becomes stable again for all ratios less than 0.0285.

Code:
2m/M     years stable
0.05	    21
0.041	   430
0.04	10000+
0.0388	10000+
0.0386	10000+
0.0385	10000+
0.031	10000+
0.03	   800
0.299	   658
0.0295	   400
0.0294	   450
0.0293	   400
0.029	   400
0.0289	   440
0.0288	   490
0.0287	   536
0.0286	   990
0.0285	10000+
0.028	10000+
0.02	10000+

A book called "The Three-Body Problem" by Christian Marchal verifies this strange island of instability around 0.029 in Chapter 8, although he computes it with math rather than simulating it like I did, and concludes that there are 2 stable regions: 0 <= R < 0.02860...and 0.02860... < R <= 0.03852.

In these examples, the mass ratio between the planet and the trojan object is 1:1. I believe that the above results (both numerical and analytic) would change, but not by much, if you altered this 1:1 ratio.
 
  • #5
[add]
I've taken a more detailed look at your results:

Interestingly enough, there does seem to be something going on here that I'm not familiar with. The equation that I give below predicts that instability starts when m/M = .019819, or 2m/M [itex]\approx[/itex] .0396

The stability analysis I did was a purely linear one - what sort did the author do in your textbook?

The results that I know about are as follows:

In order for three massive bodies to be stable (as defined by a linear analysis) one must have the following relationship between their masses:[tex] 27 \, (m_1*m_2 + m_2*m_3 + m_3*m_1) < (m_1 + m_2 + m_3)^2 [/tex]

The best literature reference I have for this is Volume 5 of of "What's Happening in the Mathematical Sciences" by Barry Cipra.

If m_3 is zero, this reduces to the usual relationship (see for instance http://www.physics.montana.edu/faculty/cornish/lagrange.pdf for the usual 2-body case).

Once upon I time I took it upon myself to confirm this result via a rather involved computer analysis based on the Hamiltonian approach. One can find a summary of what's involved in the following post.

http://groups.google.com/group/rec.arts.sf.science/msg/1fd8079db42c1137?

Basically one writes down the Hamiltonian (preferred over the Lagrangian in this case because it gives a first order system of differential equations).

One then can linearize the resulting equations, and by computing the eigienvalues of a 12x12 matrix formed from a series of partial derivatives of the Hamiltonian, one can find the above stability conditions.

Your (Tony's) gravity simulator program should be able to empirically demonstrate the above results - when I was working on this myself, a long time ago, I ran some simulations as a first step to see if the equation above worked. (Another poster, Joseph H, originally gave me the equation, as you can see if you dig back in the history of the news thread above). The simulations I did gave unstable behavior when the equations were violated, and stable behavior when they were satisfied.

Apparently, however, you've already done some work in this area, and gotten different results. Interesting.
 
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FAQ: Why objects at lagrangian points 4 and 5 are stable?

Why are objects at Lagrangian points 4 and 5 considered stable?

Objects at Lagrangian points 4 and 5 are considered stable because they are located in a region of space where the gravitational forces of two large bodies, such as a planet and its moon, balance out. This creates a point of equilibrium where objects can maintain a stable position without being pulled towards one of the larger bodies.

How do objects maintain their position at Lagrangian points 4 and 5?

Objects at Lagrangian points 4 and 5 maintain their position by constantly adjusting their orbits due to the gravitational forces of the two larger bodies. This allows them to stay in a stable position relative to the two bodies.

Are objects at Lagrangian points 4 and 5 completely stationary?

No, objects at Lagrangian points 4 and 5 are not completely stationary. They are constantly moving and orbiting around the two larger bodies, but they maintain a stable position relative to the two bodies due to the balance of gravitational forces.

Can objects at Lagrangian points 4 and 5 be affected by other forces?

Yes, objects at Lagrangian points 4 and 5 can still be affected by other forces, such as solar radiation pressure or gravitational pull from other nearby bodies. However, these forces are typically much weaker compared to the gravitational forces of the two larger bodies, so they do not significantly impact the stability of the objects at these points.

Why are Lagrangian points 4 and 5 important for space exploration?

Lagrangian points 4 and 5 are important for space exploration because they provide a relatively stable location for spacecraft and satellites to orbit. This allows for longer and more efficient missions, as the spacecraft do not need to constantly use fuel to maintain their position. They are also useful for scientific research, as they provide a unique vantage point for observing the interactions between the two larger bodies.

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