- #36
stevebd1
Gold Member
- 750
- 41
Jorrie said:[tex] \Delta t = \frac{\Delta a}{aH_0\sqrt{\Omega_m/a^3+\Omega_r/a^4 + \Omega_\Lambda}}[/tex]
Hi Jorrie, as you probably already know, that works out. The answer I get is -0.000051504 Gyrs which is -51,504 years, close to what it was estimated to be (-53,000 yrs). As you previously stated, [itex]\Delta z = 10[/itex] would probably give more accuracy.
Steve
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