- #211
JesseM
Science Advisor
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Fair enough, as long as you agree that the total universe could also be much larger than the observable universe.neopolitan said:Not really, if the universe is bigger (and curved) you just need longer rods for your triangle to make a noticeable difference in the sum of internal angles. I took an optimistic case, that the observable universe is all there is.
OK, I agree that this is implied by the Copernican Principle.neopolitan said:With regard to the Schwartzschild radius argument, it is not just the radius that matters, it is the density. The argument goes a little like this:
1. The Copernican Principle states that wherever we are in the universe it looks pretty much the same (which means there is no big empty space around us into which the mass of the universe is expanding) and leads to the cosmological principle.
2. This means that our observable universe is not essentially different from the observable universe as observed from the most distant reaches of our observable universe (or the Andromeda galaxy, to use your example.)
Only if you imagine the universe is not expanding. Since it is, you can't assume that the Schwarzschild calculation can tell you whether to expect an event horizon. And note that the larger the region of space you consider, the greater the rate at which points on opposite ends of this region are moving apart due to the expansion of space.neopolitan said:4. If the radius of the observable universe and the mass/density of the observable universe matches that for an event horizon, then the universe being bigger and isotropic just means that the mass/density of the universe will be greater than that required to constitute an event horizon.
The wikipedia article gives the radius as 46.5 billion light years, not 4.65 (and I corrected the article to read 46 billion, since this is the number given in the reference they cite). So that would give a radius of 4.35 * 10^26 meters, and a volume of 3.45 * 10^80 meters^3. Multiply this by the density of 3*10^-27 kg/m^3--and this figure is based on the estimated total density of all forms of energy including dark matter and dark energy, not just the "stellar density" as you wrote--and we have a mass of about 1.0 * 10^54 kg. Multiply by 2G/c^2 to get the corresponding Schwarzschild radius and I find it works out to 1.5 * 10^27 meters, about 3.4 times larger than the actual radius--this is still fairly close, but not as close as the 1.023 difference that you got.neopolitan said:I know you have said that this equation does not apply to expanding matter, but equally, can you see that its a pretty nice match between figures here?(Figures from http://en.wikipedia.org/wiki/Observable_universe.)
The observable universe has a radius of about 4.65 billion light years, or 4.65 billion times9,460,730,472,580.8 km = 4.3*10^25 m.
This gives a volume of 3.6*10^77 cubic metres.
The observable universe is calculated to have a mass of 3*10^52 kg - this is taken from the measured stellar density of 3*10^-27 kg/cubic metre (wikipedia contributers did this calculation, not me).
The Schwartzschild radius for the mass of the observable universe is:
r=2Gm/c^2=2*6.67*10^-11*3*10^52/(3*10^8)^2=4.4*10^25 m
Remember if the radius is greater, then the density of the universe has to be lower than has been measured and I have only ever heard arguments for the reverse, that the density of the universe is greater than measured because of "dark matter".