- #1
Faultline369
- 3
- 0
Hi!
I am new here, and I am no professional physicist, but I love science and physics. I don’t claim to know much at all, but I hope to someday. Nor am I a math wiz, in fact, I struggle with it.
With that said, I was wondering if a percentage of the reciprocal of the “Atomic volume” is the number of moles of atoms per cm3.
For example: Lead’s atomic volume is 18.272 cm3/mol. It is FCC packed, so there is actually only 74% lead and the rest is void. Therefore: 0.74 * (1 / 18.272) would equal the number of mols of just Lead atoms in One cm3 . . . right?
So multiplying that above answer by Avogadro’s# would then give the “total number of individual lead atoms” per cm3? . . . right?
Then dividing 1 cm3 by this “total number of individual lead atoms” would then yield the volume of One single atom? (this would be a reciprocal again)
If this is wrong, could you take a second and show me (if possible) how to get individual atom volume from atomic volume?
THANKS!
I am new here, and I am no professional physicist, but I love science and physics. I don’t claim to know much at all, but I hope to someday. Nor am I a math wiz, in fact, I struggle with it.
With that said, I was wondering if a percentage of the reciprocal of the “Atomic volume” is the number of moles of atoms per cm3.
For example: Lead’s atomic volume is 18.272 cm3/mol. It is FCC packed, so there is actually only 74% lead and the rest is void. Therefore: 0.74 * (1 / 18.272) would equal the number of mols of just Lead atoms in One cm3 . . . right?
So multiplying that above answer by Avogadro’s# would then give the “total number of individual lead atoms” per cm3? . . . right?
Then dividing 1 cm3 by this “total number of individual lead atoms” would then yield the volume of One single atom? (this would be a reciprocal again)
If this is wrong, could you take a second and show me (if possible) how to get individual atom volume from atomic volume?
THANKS!