- #176
ThomasT
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In any version of Bell's theoremEye_in_the_Sky said:This thread began with a post in which it was writtenello, akhmeteli. It appears to me there may be some misconception in the way you are thinking about Bell's theorem.
Bell's theorem, per se, is nothing more than a proposition of the form
P → D ,
where "P" is the conjunction of some set of premises, the 'truth' of which does not in any way require the 'truth' of any of the premises of Quantum Mechanics, and "D" is a certain condition (e.g. a Bell inequality).
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Now, it happens that Quantum Mechanics (let us denote its premises by "QM") is such that
QM → ~D .
Therefore, the conjunction "P Λ QM" is inconsistent.
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In the weak version of Bell's theorem
P = local determinism .
In the strong version of Bell's Theorem
P = locality Λ PC Λ CF ,
where
PC ≡ perfect anti-correlation for equal settings
and
CF ≡ counterfactuality .
In the strong version, of course, "PC" has been employed as premise; but this means only that we are considering any theory which admits "PC" as a feature.
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... Do you see what I am saying?
P = statistical independence
and
P → D
where D is a Bell inequality .
We observe that
QM → ~D
and
Experiment → ~D .
Therefore, the conjunctions "P Λ QM" and "P Λ Experiment" are inconsistent.
This is all that can be said vis QM's incompatibility with Bell local formulations, and experimental violations of Bell inequalities.