- #71
JesseM
Science Advisor
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Yes, I checked it, and it was wrong.JenniT said:The Pab++ example can be checked right now. It is the worked example in the PDF.
Yes, I was looking just at the PDF. There you write thatJenniT said:This is rushed, but are you looking at the right table. The PDF has the correct result.
Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6=(2Sab + 2Pab++)/6=Sab/2
But with the specific examples I gave of a=240,b=120,c=0 it is trivial to see that they are not equal:
(2Sab + Cac.Sbc + Sac.Cbc)/6=0.3125
Sab/2=0.375
So these are not equal to one another, and if we use Pab++=0.3125 neither of these is equal to (2Sab + 2Pab++)/6=0.3541666... If we use Pab++=0.375 then it is true that (2Sab + 2Pab++)/6 = Pab++, but neither of these is consistent with the earlier equation in the PDF saying that Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6.
In post #33 you continue to use the incomprehensible language of "bi-angles", but in any case it's clear that the equation Pab++ = P3 + P4 = (Cac.Sbc + Sac.Cbc)/2 from post #33 is inconsistent with the PDF's equation of Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6, because with a=240,b=120,c=0 we have:JenniT said:The substitutions that you query are given in post #33.
There you will see: Pab++ = P3 + P4 = (Cac.Sbc + Sac.Cbc)/2.
(Cac.Sbc + Sac.Cbc)/2 = (0.25*0.75 + 0.75*0.25)/2 = 0.1875
whereas
(2Sab + Cac.Sbc + Sac.Cbc)/6=(2*0.75 + 0.25*0.75 + 0.75*0.25)/6 = 1.875/6 = 0.3125
and neither of these are equal to
Sab/2 = 0.375
Please check this numerical example yourself before responding, you'll see that what I say is correct.
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