- #1,471
Gilles
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John, the figures are totally inconsistent with http://en.wikipedia.org/wiki/Spontaneous_fission" . The decay half-life of U235 is 7E8 years, i.e 2.E16 s - so we have a decay rate of 5E-17 per second and per nucleus. The fission probability is 7E-11 - meaning 4E-27 fission per nucleus per second. In 1 t of U235, you have 1E6/235 *6E23 = 2.5E27 nuclei, so around 10 fissions per t per second. If I-134 concentration is the result of a steady state between production and decay, the production rate must exactly balance the decay rate : the reported activity is 2.9 billion Bq/cm^3 = meaning a production rate of 2.9 billions of nuclei per s and per cm^3 - just multiply by the volume of water and you'll have an idea of the numbers of fission events you need (actually it's more because you still have to correct from the I-134 yield ). We are orders and orders of magnitude over spontaneous fission.John5656 said:So even though we have a scram, surely some decay will be occurring, producing the short half lives found...? We don't have to have a chain reaction to find them, or do we?
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