- #71
pmb_phy
- 2,952
- 1
Note - Don't be too surprised if you see this relation in an SR text with the E missing. Sometimes the authors leave the m (rel-mass) in and leave out the Ecybermambo said:You are completely correct selfAdjoint. The 4 vector derivation follows precisely as:
Start with the vector:
(cdt,dx,dy,dz)
Divide by proper time dτ=dt/γ and define as V:
V ≡ γ(c,dx/dt,dy/dt,dz/dt) = (γc,γv)
Multiply by m and define as P:
P ≡ (γmc,γmv)
Multiply by c:
Pc = (γmc2,γmvc) = (E,pc)
Take the inner product of Pc·Pc:
Pc·Pc = (γmc2)2 - (γmvc)2
The value of the inner product is invariant and can be found most easily by choosing v=0:
(γmc2)2 - (γmvc)2 = (mc2)2
Rearrange and we get:
E2 = (pc)2 + (mc2)2
Pete