- #1
yuiop
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Hi,
could someone clarify some concepts and definitions for me, concerning how velocity and acceleration are measured?
Please consider the following setup (to keep it simple for me )
We have a linear accelerator in a lab. A small mass (maybe a proton) is accelerated to 0.8c in one second. The accelerator is designed to accelerate the mass with constant proper acceleration. All motion is in a straight line and I only want to consider motion along the x-axis and time t.
0.8c is the velocity measured in the lab frame in the normal way as v=x/t. (Thats the 3 velocity right?)
From the relativistic rocket equations http://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html the proper acceleration (a) can be found from the equation:
[tex] a = \frac{v}{t\sqrt{1-(v/c)^2}}[/tex]
which with t=1 second and v=0.8c as measured in the lab the value of the constant proper acceleration works out as 1.3333
So after 1 second in the lab frame with constant proper acceleration of 1.3333 what is the:
Proper velocity of the particle? (I assume zero?)
3 velocity of the particle in the lab frame? (I assume 0.8c?)
4 velocity of the particle? (c?)
Proper acceleration of the particle? (1.3333 assumed)
3 acceleration of the particle in the lab frame? (I assume 1.3333/gamma^3)?
4 acceleration of the particle?
where gamma is 1/0.6 calculated from the instaneous velocity of 0.8c
Also, what is the:
Proper force acting on the particle?
3 force acting on the particle?
4 force acting on the particle?
After 2 seconds with constant acceleration the velocity of the particle in the lab would be
[tex] v = \frac{at}{\sqrt{1+(at/c)^2}} = 0.93633c [/tex]
what would the corresponding proper, 3 and 4 vector quantities be after 2 seconds?
If you can give any additional insight as to what the terms mean in a practical sense that would be very much appreciated
It is often mentioned that acceleration and the force causing the acceleration are not always parallel in relativity. I assume that is not he case in this particular example?
could someone clarify some concepts and definitions for me, concerning how velocity and acceleration are measured?
Please consider the following setup (to keep it simple for me )
We have a linear accelerator in a lab. A small mass (maybe a proton) is accelerated to 0.8c in one second. The accelerator is designed to accelerate the mass with constant proper acceleration. All motion is in a straight line and I only want to consider motion along the x-axis and time t.
0.8c is the velocity measured in the lab frame in the normal way as v=x/t. (Thats the 3 velocity right?)
From the relativistic rocket equations http://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html the proper acceleration (a) can be found from the equation:
[tex] a = \frac{v}{t\sqrt{1-(v/c)^2}}[/tex]
which with t=1 second and v=0.8c as measured in the lab the value of the constant proper acceleration works out as 1.3333
So after 1 second in the lab frame with constant proper acceleration of 1.3333 what is the:
Proper velocity of the particle? (I assume zero?)
3 velocity of the particle in the lab frame? (I assume 0.8c?)
4 velocity of the particle? (c?)
Proper acceleration of the particle? (1.3333 assumed)
3 acceleration of the particle in the lab frame? (I assume 1.3333/gamma^3)?
4 acceleration of the particle?
where gamma is 1/0.6 calculated from the instaneous velocity of 0.8c
Also, what is the:
Proper force acting on the particle?
3 force acting on the particle?
4 force acting on the particle?
After 2 seconds with constant acceleration the velocity of the particle in the lab would be
[tex] v = \frac{at}{\sqrt{1+(at/c)^2}} = 0.93633c [/tex]
what would the corresponding proper, 3 and 4 vector quantities be after 2 seconds?
If you can give any additional insight as to what the terms mean in a practical sense that would be very much appreciated
It is often mentioned that acceleration and the force causing the acceleration are not always parallel in relativity. I assume that is not he case in this particular example?
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