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atavistic
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In an inductor capacitor circuit , what is the kind of E field driving the current? Conservative or non-conservative? And I really don't understand what is the correct way to setup the differential equation for it. This is why:
In high school level textbooks(Resnick Walker), they have applied loop rule.
In Griffith, he says [tex]\epsilon[/tex] = -L di/dt = Q/C
In MIT OCW , walter lewin says [tex]\int[/tex] E.dl = -Ldi/dt = Q/C
I think last two are the same but still can someone clear this.I mean going by what griffith says(hes the best) can someone tell me why is [tex]\epsilon[/tex] = -L di/dt . I know [tex]\epsilon[/tex] = [tex]\int[/tex]f.dl . How can I arrive using [tex]\int[/tex]f.dl that the [tex]\epsilon[/tex] in the circuit is -Ldi/dt. This thing has been bugging me a lot, please reply.
[tex]\epsilon[/tex] = EMF and [tex]\int[/tex] = closed loop integral.
In high school level textbooks(Resnick Walker), they have applied loop rule.
In Griffith, he says [tex]\epsilon[/tex] = -L di/dt = Q/C
In MIT OCW , walter lewin says [tex]\int[/tex] E.dl = -Ldi/dt = Q/C
I think last two are the same but still can someone clear this.I mean going by what griffith says(hes the best) can someone tell me why is [tex]\epsilon[/tex] = -L di/dt . I know [tex]\epsilon[/tex] = [tex]\int[/tex]f.dl . How can I arrive using [tex]\int[/tex]f.dl that the [tex]\epsilon[/tex] in the circuit is -Ldi/dt. This thing has been bugging me a lot, please reply.
[tex]\epsilon[/tex] = EMF and [tex]\int[/tex] = closed loop integral.