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noppawit
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Beverage engineering. The pull tab was a major advance in the engineering design of beverage containers. The tab pivots on a central bolt in the can's top. When you pull upward on one end of the tab, the other end presses downward on a portion of the can's top that has been scored. If you pull upward with a 10N force, approximately what is the magnitude of the force applied to the scored section? (You will need to examine a can with a pull tab.)
After I measure the pull tab, I got:
Pull tab length is 2.5cm
From pulling zone to pivot is 1.75cm, let it = R
and from pivot to pressing zone is 0.75, let it = r
Given, pull upward 10N
Can I calculate by using
F1R = F2r
10 * 1.75 = 0.75 * F2
Fpressing = 23.33N
Is this correct?
After I measure the pull tab, I got:
Pull tab length is 2.5cm
From pulling zone to pivot is 1.75cm, let it = R
and from pivot to pressing zone is 0.75, let it = r
Given, pull upward 10N
Can I calculate by using
F1R = F2r
10 * 1.75 = 0.75 * F2
Fpressing = 23.33N
Is this correct?