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prateek_34gem
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Power Question !Need Help
A particle of mass 'm' is moving in a Circular path of constant radius 'r' such that it's centripetal acceleration is given by ac= k2rt2 where k is constant. The power delivered to the particle by the force acting on it is :-
A) 2(pi)mk2r2t
B) mk2r2t
C) (mk4r2t5)/3
D) zero
Centripetal force will be f=mac so f=mk2rt2.
Now, Centripetal acceleration = v2/r.
so v= krt
now,
power = force*distance/time for which work is done
(mk2rt2*vt)/t
from this i am getting power as mk3r2t3.
Homework Statement
A particle of mass 'm' is moving in a Circular path of constant radius 'r' such that it's centripetal acceleration is given by ac= k2rt2 where k is constant. The power delivered to the particle by the force acting on it is :-
A) 2(pi)mk2r2t
B) mk2r2t
C) (mk4r2t5)/3
D) zero
Homework Equations
The Attempt at a Solution
Centripetal force will be f=mac so f=mk2rt2.
Now, Centripetal acceleration = v2/r.
so v= krt
now,
power = force*distance/time for which work is done
(mk2rt2*vt)/t
from this i am getting power as mk3r2t3.
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