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This remarkable claim was made over in the "Special & General Relativity" forum of this site, in post #3 of this thread, and then subsequently discussed in posts #9, #11, #16, and all posts from #19 onwards in that thread. Please read those posts and then respond here.Mentz114 said:"Photons" only exist at the moment they are emitted or absorbed i.e. when they interact with matter. There is no evidence ( nor any way of getting any ) that photons exist in the EM field when it is not interacting with matter.
Speculations about 'free' photons usually lead to apparent contradictions, as evidenced by your question.
To my way of thinking, this is absurd use of language. But sometimes absurd things happen in quantum theory so I'm posing the question here to see what experts think.
As I understand it, the claim is based on the premise that photons can be measured only by emission or absorption. I can accept that premise, and photons are considered to take all possible routes between those events so it is impossible to determine the position of a photon between emission and absorption. But to claim that because we choose not to measure a photon's position then the photon "does not exist" seems to me to be an abuse of the English language. The claim seems to suggest that the lifetime of a photon is:
1. Photon emitted
2. Photon immediately ceases to exist
3. Some time later, photon comes back into existence
4. Photon is immediately absorbed.
That just sounds like nonsense to me. Just because we choose not to detect a photon between two events A and B does not mean we could not have detected the photon had we tried to do so. If we tried, we would succeed, but then event B would not occur because our detection would have absorbed the photon.
Am I talking sense, or is the original quote in this post actually meaningful?
(My knowledge of quantum theory isn't too deep, but I understand the basics.)