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In Fredrik's recent thread:
https://www.physicsforums.com/showthread.php?t=506326
some questions arose about this paper:
J. B. Hartle, "Quantum Mechanics of Individual Systems",
Am. J. Phys., vol 36, no 8, (1968), pp704-712.
[For other readers, you'll need to have read or be able to access a
copy of Hartle's paper above for what follows to make most sense.]
In that paper, Hartle claims to derive statistical aspects of QM (aka
Born rule) from the nonstatistical aspects of QM. Fredrik was skeptical
about whether Hartle's paper really does derive the Born rule, and had
various other doubts about the content of the paper. Since this is all a
bit tangential to the main topic of his thread, I post my attempt at a
more detailed explanation here as a separate thread.
Let A be an observable with eigenvalues and eigenvectors as follows:
[tex]
\def\<{\langle}
\def\>{\rangle}
\def\half{\frac{1}{2}}
\def\third{\frac{1}{3}}
A |i\> = a_i |i\>
[/tex]
In QM, one asserts that the value of the observable A measured in state
[itex]|i\>[/itex] is [itex]a_i[/itex] and that this is definite (i.e., deterministic).
This is called a "nonstatistical" assertion of QM about an individual system
modeled by [itex]|i\>[/itex].
Hartle's assertion (p706, lower right) is that the statistical predictions
of QM can be recovered from QM's nonstatistical assertions about
individual systems. His argument involves constructing an N-fold tensor
product space and depends on a particular interpretation of the following
operator acting on that space [see Hartle's eq(5)]:
[tex]
f_N^k ~:= \sum_{i_1,\cdots,i_N} |i_1,1\> \cdots |i_N,N\>
\left( \frac{1}{N} \sum_{\alpha=1}^N \delta_{k i_\alpha} \right)
\<i_N,N| \cdots \<i_1,1|
[/tex]
which Hartle calls the frequency operator. The sum over each
[itex]i[/itex] parameter means we are summing over the eigenvectors of A
in each (mutually independent) component space of the N-fold tensor
product space. The component spaces are used to model independent
repetitions of the experiment (such that the prepared state of the system
may or may not all be the same).
To explain why [itex]f_N^k[/itex] deserves the name "frequency operator"
we consider some specific cases. For the trivial case N=1, the frequency
operator reduces to
[tex]
f_1^k ~=~ \sum_{i_1} |i_1,1\> \left( \delta_{k i_1} \right) \<i_1,1|
[/tex]
or, dropping the component space label (which is unnecessary when N=1),
[tex]
f_1^k ~=~ \sum_{i} |i\> \delta_{ki} \<i| ~=~ |k\>\<k|
[/tex]
For N=2, the frequency operator is
[tex]
\begin{align}
f_2^k
&= \sum_{i_1,i_2} |i_1,1\> |i_2,2\>
\Big( \half \sum_{\alpha=1}^2 \delta_{k i_\alpha} \Big)
\<i_2,2| \<i_1,1| \\
&= \sum_{i_1,i_2} |i_1,1\> |i_2,2\>
\half \Big( \delta_{k i_1} + \delta_{k i_2} \Big)
\<i_2,2| \<i_1,1| \\
&= \half\Big(
\sum_{i_1,i_2} |i_1,1\> |i_2,2\> \delta_{k i_1} \<i_2,2| \<i_1,1|
~+~ \sum_{i_1,i_2} |i_1,1\> |i_2,2\> \delta_{k i_2} \<i_2,2| \<i_1,1|
\Big) \\
&= \half\Big(
\sum_{i_2} |k,1\> |i_2,2\> \<i_2,2| \<k,1|
~+~ \sum_{i_1} |i_1,1\> |k,2\> \<k,2| \<i_1,1| \Big) \\
&= \half\Big( |k,1\> \<k,1| ~+~ |k,2\> \<k,2| \Big)
\end{align}
[/tex]
where we have used the mathematical theorem that the eigenvectors of
the self-adjoint operator A give a resolution of unity. Note that each term in
the last line above includes an implicit identity operator on the other
component space of the 2-fold tensor product, e.g.,
[tex]
|k,1\> \<k,1|
[/tex]
acts as a projector on component space 1, but as the identity on
component space 2.
Similarly, for N=3 we find
[tex]
f_3^k
~=~ \third\Big( |k,1\> \<k,1| ~+~ |k,2\> \<k,2| ~+~ |k,3\> \<k,3| \Big)
[/tex]
and so on. Perhaps it would have been clearer to define the
frequency operator as
[tex]
f_N^k
~=~ \frac{1}{N} \sum_{\alpha=1}^N |k,\alpha\> \<k,\alpha|
[/tex]
Consider now how [itex]f_3^k[/itex] acts on three independent experiments,
with preparations corresponding to definite outcomes, i.e., eigenstates of A.
If the sequential preparations are, respectively, [itex]|j,1\>[/itex], [itex]|k,2\>[/itex], [itex]|k,3\>[/itex] (with [itex]j\ne k[/itex]),
then [itex]f_3^k[/itex] acts on the tensor product of these states as follows:
[tex]
\begin{align}
f_3^k ~ |j,1\> |k,2\> |k,3\>
&= \third\Big( |k,1\> \<k,1| ~+~ |k,2\> \<k,2| ~+~ |k,3\> \<k,3| \Big)
|j,1\> |k,2\> |k,3\> \\
&= \frac{2}{3} \; |j,1\> |k,2\> |k,3\>
\end{align}
[/tex]
giving the correct answer that [itex](2/3)[/itex] of the initial preparations were in state [itex]|k\>[/itex].
This is the justification for calling [itex]f_N^k[/itex] a "frequency
operator" -- in the following sense. Hartle takes the nonstatistical
aspects of QM as given. Initial states prepared in an eigenstate of A
fall into this category: the result of measuring A for any of these
states is definite (deterministic). [This is analogous to a
sequence of trivial classical experiments in which a state is prepared
(e.g., a coin laid flat on a table by Ian) and then examined (without
tossing the coin) by Fred. Fred always observes precisely whatever state
Ian prepared.]
Now we investigate the behaviour of [itex]f_N^k[/itex] applied to the
product of N copies of an arbitrary state [itex]|s\>[/itex] which is
in general a linear combination of the [itex]|i\>[/itex] eigenstates of
A. We denote N-fold tensor product state in an abbreviated form:
[tex]
|(s)^N\> ~:=~ |s,1\> |s,2\> \cdots |s,N\>
[/tex]
Hartle shows that
[tex]
\lim_{N\to\infty} \Big( f_N^k - |\<k|s\>|^2 \Big) |(s)^N\> ~=~ 0
[/tex]
In other words we may say that, [itex]|(s)^\infty\>[/itex] is an eigenstate of [itex]f_\infty^k[/itex] with eigenvalue [itex]|\<k|s\>|^2[/itex].
Relying again on the nonstatistical aspects of QM, this means that if we measure
the observable [itex]f_\infty^k[/itex] for the state [itex]|(s)^\infty\>[/itex] we definitely get [itex]|\<k|s\>|^2[/itex].
All that now remains is the question of whether it's still reasonable to call
[itex]f_\infty^k[/itex] a "frequency" operator when applied to states that are not
eigenstates of A.
First, consider other well-known observables in QM, such as momentum or spin.
We construct the associated operators so that they have the physically correct
spectrum of eigenvalues. (Operationally, this corresponds to the set of outcomes
possible from an apparatus which "measures" that observable, which has itself been
designed and calibrated by preparing certain states and verifying that the apparatus
always gives the same answer whenever presented with that particular prepared state).
In other words, the candidate operator must give the correct answer in every classical
(deterministic) case.
But that's exactly what Hartle did in defining his frequency operator. He constructed
it so that it gave the physically correct answers when applied to its (finite-N) eigenstates.
So the answer to the question of why it's reasonable to say that [itex]f_N^k[/itex] is a
"frequency" operator is essentially the same as the answer to why it's reasonable to
consider [itex]i\partial_x[/itex] a "momentum" operator when acting on a space of
functions: it has the physically sensible set of eigenvalues, as verified by its action on
states which we expect physically should be its eigenstates, corresponding to
deterministic classical cases.
https://www.physicsforums.com/showthread.php?t=506326
some questions arose about this paper:
J. B. Hartle, "Quantum Mechanics of Individual Systems",
Am. J. Phys., vol 36, no 8, (1968), pp704-712.
[For other readers, you'll need to have read or be able to access a
copy of Hartle's paper above for what follows to make most sense.]
In that paper, Hartle claims to derive statistical aspects of QM (aka
Born rule) from the nonstatistical aspects of QM. Fredrik was skeptical
about whether Hartle's paper really does derive the Born rule, and had
various other doubts about the content of the paper. Since this is all a
bit tangential to the main topic of his thread, I post my attempt at a
more detailed explanation here as a separate thread.
Let A be an observable with eigenvalues and eigenvectors as follows:
[tex]
\def\<{\langle}
\def\>{\rangle}
\def\half{\frac{1}{2}}
\def\third{\frac{1}{3}}
A |i\> = a_i |i\>
[/tex]
In QM, one asserts that the value of the observable A measured in state
[itex]|i\>[/itex] is [itex]a_i[/itex] and that this is definite (i.e., deterministic).
This is called a "nonstatistical" assertion of QM about an individual system
modeled by [itex]|i\>[/itex].
Hartle's assertion (p706, lower right) is that the statistical predictions
of QM can be recovered from QM's nonstatistical assertions about
individual systems. His argument involves constructing an N-fold tensor
product space and depends on a particular interpretation of the following
operator acting on that space [see Hartle's eq(5)]:
[tex]
f_N^k ~:= \sum_{i_1,\cdots,i_N} |i_1,1\> \cdots |i_N,N\>
\left( \frac{1}{N} \sum_{\alpha=1}^N \delta_{k i_\alpha} \right)
\<i_N,N| \cdots \<i_1,1|
[/tex]
which Hartle calls the frequency operator. The sum over each
[itex]i[/itex] parameter means we are summing over the eigenvectors of A
in each (mutually independent) component space of the N-fold tensor
product space. The component spaces are used to model independent
repetitions of the experiment (such that the prepared state of the system
may or may not all be the same).
To explain why [itex]f_N^k[/itex] deserves the name "frequency operator"
we consider some specific cases. For the trivial case N=1, the frequency
operator reduces to
[tex]
f_1^k ~=~ \sum_{i_1} |i_1,1\> \left( \delta_{k i_1} \right) \<i_1,1|
[/tex]
or, dropping the component space label (which is unnecessary when N=1),
[tex]
f_1^k ~=~ \sum_{i} |i\> \delta_{ki} \<i| ~=~ |k\>\<k|
[/tex]
For N=2, the frequency operator is
[tex]
\begin{align}
f_2^k
&= \sum_{i_1,i_2} |i_1,1\> |i_2,2\>
\Big( \half \sum_{\alpha=1}^2 \delta_{k i_\alpha} \Big)
\<i_2,2| \<i_1,1| \\
&= \sum_{i_1,i_2} |i_1,1\> |i_2,2\>
\half \Big( \delta_{k i_1} + \delta_{k i_2} \Big)
\<i_2,2| \<i_1,1| \\
&= \half\Big(
\sum_{i_1,i_2} |i_1,1\> |i_2,2\> \delta_{k i_1} \<i_2,2| \<i_1,1|
~+~ \sum_{i_1,i_2} |i_1,1\> |i_2,2\> \delta_{k i_2} \<i_2,2| \<i_1,1|
\Big) \\
&= \half\Big(
\sum_{i_2} |k,1\> |i_2,2\> \<i_2,2| \<k,1|
~+~ \sum_{i_1} |i_1,1\> |k,2\> \<k,2| \<i_1,1| \Big) \\
&= \half\Big( |k,1\> \<k,1| ~+~ |k,2\> \<k,2| \Big)
\end{align}
[/tex]
where we have used the mathematical theorem that the eigenvectors of
the self-adjoint operator A give a resolution of unity. Note that each term in
the last line above includes an implicit identity operator on the other
component space of the 2-fold tensor product, e.g.,
[tex]
|k,1\> \<k,1|
[/tex]
acts as a projector on component space 1, but as the identity on
component space 2.
Similarly, for N=3 we find
[tex]
f_3^k
~=~ \third\Big( |k,1\> \<k,1| ~+~ |k,2\> \<k,2| ~+~ |k,3\> \<k,3| \Big)
[/tex]
and so on. Perhaps it would have been clearer to define the
frequency operator as
[tex]
f_N^k
~=~ \frac{1}{N} \sum_{\alpha=1}^N |k,\alpha\> \<k,\alpha|
[/tex]
Consider now how [itex]f_3^k[/itex] acts on three independent experiments,
with preparations corresponding to definite outcomes, i.e., eigenstates of A.
If the sequential preparations are, respectively, [itex]|j,1\>[/itex], [itex]|k,2\>[/itex], [itex]|k,3\>[/itex] (with [itex]j\ne k[/itex]),
then [itex]f_3^k[/itex] acts on the tensor product of these states as follows:
[tex]
\begin{align}
f_3^k ~ |j,1\> |k,2\> |k,3\>
&= \third\Big( |k,1\> \<k,1| ~+~ |k,2\> \<k,2| ~+~ |k,3\> \<k,3| \Big)
|j,1\> |k,2\> |k,3\> \\
&= \frac{2}{3} \; |j,1\> |k,2\> |k,3\>
\end{align}
[/tex]
giving the correct answer that [itex](2/3)[/itex] of the initial preparations were in state [itex]|k\>[/itex].
This is the justification for calling [itex]f_N^k[/itex] a "frequency
operator" -- in the following sense. Hartle takes the nonstatistical
aspects of QM as given. Initial states prepared in an eigenstate of A
fall into this category: the result of measuring A for any of these
states is definite (deterministic). [This is analogous to a
sequence of trivial classical experiments in which a state is prepared
(e.g., a coin laid flat on a table by Ian) and then examined (without
tossing the coin) by Fred. Fred always observes precisely whatever state
Ian prepared.]
Now we investigate the behaviour of [itex]f_N^k[/itex] applied to the
product of N copies of an arbitrary state [itex]|s\>[/itex] which is
in general a linear combination of the [itex]|i\>[/itex] eigenstates of
A. We denote N-fold tensor product state in an abbreviated form:
[tex]
|(s)^N\> ~:=~ |s,1\> |s,2\> \cdots |s,N\>
[/tex]
Hartle shows that
[tex]
\lim_{N\to\infty} \Big( f_N^k - |\<k|s\>|^2 \Big) |(s)^N\> ~=~ 0
[/tex]
In other words we may say that, [itex]|(s)^\infty\>[/itex] is an eigenstate of [itex]f_\infty^k[/itex] with eigenvalue [itex]|\<k|s\>|^2[/itex].
Relying again on the nonstatistical aspects of QM, this means that if we measure
the observable [itex]f_\infty^k[/itex] for the state [itex]|(s)^\infty\>[/itex] we definitely get [itex]|\<k|s\>|^2[/itex].
All that now remains is the question of whether it's still reasonable to call
[itex]f_\infty^k[/itex] a "frequency" operator when applied to states that are not
eigenstates of A.
First, consider other well-known observables in QM, such as momentum or spin.
We construct the associated operators so that they have the physically correct
spectrum of eigenvalues. (Operationally, this corresponds to the set of outcomes
possible from an apparatus which "measures" that observable, which has itself been
designed and calibrated by preparing certain states and verifying that the apparatus
always gives the same answer whenever presented with that particular prepared state).
In other words, the candidate operator must give the correct answer in every classical
(deterministic) case.
But that's exactly what Hartle did in defining his frequency operator. He constructed
it so that it gave the physically correct answers when applied to its (finite-N) eigenstates.
So the answer to the question of why it's reasonable to say that [itex]f_N^k[/itex] is a
"frequency" operator is essentially the same as the answer to why it's reasonable to
consider [itex]i\partial_x[/itex] a "momentum" operator when acting on a space of
functions: it has the physically sensible set of eigenvalues, as verified by its action on
states which we expect physically should be its eigenstates, corresponding to
deterministic classical cases.