- #1
jpcjr
- 17
- 0
1. Homework Statement
NOTE: I realize the following is a partial differential equation, but I believe the answer to my question is a straight forward multi-variate calculus question.
Let v(x,t) = u(x+ct,t) and show that v(x,t) solves the following...
ut = κ uxx ; (-∞<x<∞)
u(x,0) = [itex]\phi[/itex](x)
NOTE: You may disregard the following, if necessary for you to answer this question:
u(x,0) = [itex]\phi[/itex](x)
and simply show that v(x,t) solves the following...
ut = κ uxx
ALTERNATIVELY, you may help me by commenting on the correctness of my work below.
2. Homework Equations
See above and below...
3. The Attempt at a Solution
v(x,t) = u(x+ct,t)
v'(x,t) = c u[itex]_{x}[/itex](x+ct,t) + u[itex]_{t}[/itex](x+ct,t)
v[itex]_{x}[/itex](x,t) = c u[itex]_{x}[/itex](x+ct,t)
v[itex]_{xx}[/itex](x,t) = c[itex]^{2}[/itex] u[itex]_{xx}[/itex](x+ct,t)
v[itex]_{t}[/itex](x,t) = u[itex]_{t}[/itex](x+ct,t)
NOTE: I realize the following is a partial differential equation, but I believe the answer to my question is a straight forward multi-variate calculus question.
Let v(x,t) = u(x+ct,t) and show that v(x,t) solves the following...
ut = κ uxx ; (-∞<x<∞)
u(x,0) = [itex]\phi[/itex](x)
NOTE: You may disregard the following, if necessary for you to answer this question:
u(x,0) = [itex]\phi[/itex](x)
and simply show that v(x,t) solves the following...
ut = κ uxx
ALTERNATIVELY, you may help me by commenting on the correctness of my work below.
2. Homework Equations
See above and below...
3. The Attempt at a Solution
v(x,t) = u(x+ct,t)
v'(x,t) = c u[itex]_{x}[/itex](x+ct,t) + u[itex]_{t}[/itex](x+ct,t)
v[itex]_{x}[/itex](x,t) = c u[itex]_{x}[/itex](x+ct,t)
v[itex]_{xx}[/itex](x,t) = c[itex]^{2}[/itex] u[itex]_{xx}[/itex](x+ct,t)
v[itex]_{t}[/itex](x,t) = u[itex]_{t}[/itex](x+ct,t)