Angular resolution describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution. It is used in optics applied to light waves, in antenna theory applied to radio waves, and in acoustics applied to sound waves. The closely related term spatial resolution refers to the precision of a measurement with respect to space, which is directly connected to angular resolution in imaging instruments. The Rayleigh criterion shows that the minimum angular spread that can be resolved by an image forming system is limited by diffraction to the ratio of the wavelength of the waves to the aperture width. For this reason, high resolution imaging systems such as astronomical telescopes, long distance telephoto camera lenses and radio telescopes have large apertures.
Hello,
I am using a code on EUCLID future mission. The original author of this code has set a value for the density of galaxy equal to :
ng = 354543085.80106884
I think this is expressed in inverse steradian. I think that EUCLID mission has a 30 arcmin^-2 value for density of galaxies...
Homework Statement
The physical size of a single LOFAR station, operating at 150MHz is about 50m. Estimate the number of pixels which would be needed to map the full primary beam if one wished to include all LOFAR stations (maximum baseline ~ 800 km) at full resolution.
Homework Equations...
Hi.
The angular resolution is calculated through
$$\theta=1.22\frac{\lambda}{D}\enspace.$$
It's the first zero of the intensity function (in small-angle approximation) of the Airy disk...
Homework Statement
λ = 240 nm
D = 2.40 m
We are supposed to find the angle resolution (minimum angular distance between two objects so we
still see them as two separate objects) to the telescope for ultraviolet light with wavelength 240 nm
Homework Equations
The equation that I used is θ =...
Since, under rayleigh's criterion, the angular resolution is dependent on the wavelength of light, wouldn't blue light be more sharply focused by our eyes?
Homework Statement
At first I needed to calculate the angular resolution of a telescope (diameter 1m, for visible light) so I used θ=1.22λ/D and got 4.88x10^-7 rad. Now I am asked: "If we wished to use this telescope to image the moon, what is the closest distance two objects can be to be...
Homework Statement
Homework Equations
θ =1.22λ/d
The Attempt at a Solution
for (a) θ =1.22λ/d
θ =1.22(579nm)/(1.2cm)[/B]
θ =5.8865x10^-5 degree= 1.027x10^-6 rad but the answer =2x10^-3rad ,
for the micorscope, the formula of angular resolution is different?
i...
Homework Statement
Soon astronomers will be imaging the “shadow” of light from the event horizons of black holes. Since black holes are very small, this achievement seems impossible. Nevertheless, it is possible for three reasons:
1. Supermassive black holes have large event horizons.
2. Radio...
Homework Statement
An optical telescope has a diameter of 1.5m. It is placed at a site with 'seeing' of 1.0''. What is the expected resolution in arcseconds from observations made with the telescope at 1000nm? Give your answer to one decimal placeHomework Equations
Theta (rads) = 1.22 *...
The Wikipedia definition of angular resolution is 'Angular resolution, or spatial resolution, describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major...
Technological advances are now making it possible to link visible-light telescopes so that they can achieve the same angular resolution as a single telescope over 300 meters in size.
What is the angular resolution (diffraction limit) of such a system of telescopes for observations at a...
When calculating angular resolution, is it correct that having a SMALLER number results in GREATER angular resolution? For example, is 26.25" better resolution than 2625"?
Using the formula .25"(lambda in micrometre/diamter in meters), it would make sense to me that the larger the diameter...
Does anybody know of a good reference for determining the required diameter of an Earth observing telescope's primary mirror? I am trying to find determine a rough estimate for a design I am working on. So far I have found the equation
Sin\theta = 1.220 \lambda/D
for angular resolution and...
Hello all,
In terms of Radio Astronomy, can someone please explain to me the difference between the Beam Width and the Angular Resolution? I have a 1.2m dish to play about with, and I wanted to know what it could resolve. I thought I was sorted by using the diffraction formula, but then I...
My main issue with this problem is the formula and how to derive it.
Homework Statement
The Hubble Space Telescope has a resolution of about 0.05 arc second. What is the smallest object it could see on the surface of the Moon? Give your answer in metres.
Homework Equations
I tried to...
Homework Statement
A radio telescope observes two stars orbiting each other, using radio waves of wavelength 20.0 cm. The stars are 10^7m away from the Earth. The telescope, which has a diameter of 20.0km, can just resolve the two stars. What is the distance between the two stars?Homework...
Homework Statement
Two red lights are separated by 5cm, perpendicular to your line of sight. How far away from them are you if they can just be resolved with the naked eye?
Homework Equations
angular resolution =sin(theta)=1.22lambda / D
spatial resolution = 1.22(focal length * lambda)/D...
If we know the bolometric flux, spectral type, and effective temperature of a given star, how can we derive the angular resolution from the information?
This was brought up in class and I've found myself obsessing since I can't figure it out.