Hello,
I came across the question attached. To approach this, I assigned S1 to car Y and S2 to car X. So the displacement of Car Y is S1=S2 + d(naught). Then using S1= ut+(1/2) at^2 for car Y and S2= uT , I got to uT + d(naught) = VT + (1/2)aT^2. However, I am stuck here as I can't relate...
##\dfrac{x+2}{y-4} +\dfrac{2(y-4)}{x+2} + 3=0##
##x-y=3##
My approach, will call it brute force, i have
##y=x-3##
then,
##\dfrac{(x+2)^2+2(y-4)^2}{(x+2)(y-4)}=-3##
##(x+2)^2+2(y-4)^2=-3(x+2)(y-4)##
##(x+2)^2+2(x-7)^2=-3(x+2)(x-7)##
##x^2+4x+4+2(x^2-14x+49)+3(x^2-5x-14)=0##
##6x^2-39x+60=0##...
Hello frens,
How should one approach this sort of integral? Any tips would be appreciated.
Let's say we have
$$ \int_{(1)}^{(2)}\exp\left[ a+b\exp\left[ f(x) \right] \right]dx$$
...where the limits of integration are not important.
Any tips? Thanks!
My interest is on how they arrived at ##r^2 \sin θ##
My approach using the third line, is as follows
##\cos θ[r^2 \cos θ \sin θ \cos^2 ∅ + r^2 \sin θ \cos θ cos^2∅ ] + r\sin θ [r\sin^2 θ \cos^2∅ + r \sin^2 θ \sin^2 ∅]=##
##\cos θ[r^2 \cos θ \sin θ[\cos^2 ∅+ \sin^2 ∅]] + r\sin θ [r\sin^2 θ...
I am interested in an algebraic approach.
My lines are as follows;
##\dfrac{(x+1)(x+4)}{(x-1)(x-2)} -2<0##
##\dfrac{(x^2+5x+4) - 2(x-1)(x-2)}{(x-1)(x-2)} <0##
The denominator will give us the vertical asymptotes ##x=1## and ##x=2##
The numerator gives us,
##x^2+5x+4-2x^2+6x-4 <0##...
Ok in my approach i have the lines,
starting with the inner integral,
$$\int_0^1 xy \cos (x^2y) dx$$
I let ##u =x^2y , u(0)=0, u(1)=y##
...
$$\dfrac{1}{2} \int_0^y \cos u du=\left[\dfrac{1}{2} \sin u \right]_0^y= \left[\dfrac{1}{2} \sin (x^2y) \right]_0^1=\left[\dfrac{1}{2} \sin y...
A. Correct answer is radius = 1770m, acceleration = 2.73*10^-3m/s.
B. I don't know how to approach this problem. I don't know if I should start with forces, energy, or basic kinematics.
Wolfram gave the solution and a hint: i want to understand the hands on approach steps...
In my approach (following Wolfram's equation) i have,
##(x-3)^2(2+12(x-3)+(x-3)^2=-25##
##(x-3)^2((x+3)^2-33)=-25##
##(x-3)\sqrt{((x+3)^2-33)}=-5i##
...
Ok in my approach i have,
##2 \tan^{-1} \left(\dfrac{1}{5}\right)= \sin^{-1} \left(\dfrac{3}{5}\right) - \cos^{-1} \left(\dfrac{63}{65}\right)##Consider the rhs,
Let
##\sin^{-1} \left(\dfrac{3}{5}\right)= m## then ##\tan m =\dfrac{3}{4}##
also
let
##\cos^{-1} \left(\dfrac{63}{65}\right)=...
I want to use the Lagrangian approach to find the equation of motion for a mass sliding down a frictionless inclined plane. I call the length of the incline a and the angle that the incline makes with the horizontal b. Then the mass has kinetic energy 1/2m(da/dt)2 and the potential energy should...
I'd like to proceed in a linear fashion, taking each part on one by one. For the first part, we can write the Hamiltonian as ##H = \sum_{n}^{N} w(c_{An}^{\dagger}c_{Bn}+c_{Bn}^{\dagger}c_{An})+v(c_{Bn}^{\dagger}c_{A(n+1)}+c_{A(n+1)}^{\dagger}c_{Bn})##. We can convert the creation and...
TL;DR Summary: How do I approach the setup of this problem? It seems very different than a setup for a kinematics problem
I'm self studying first year mechanics and am having a hard time with the following problem (screenshot attached). The example is from Intro to Mechanics by K&K.
I'm...
Hello everyone, sorry if this is the wrong section. In this forum I'm a fish out of the bowl, my knowledge of physics is ages beyond most of the people on there, so please forgive my naivness.
So, here's my problem, I'm a sort of "audio" engineer (won't enter much on detail) and on my free...
This is a text book example- i noted that we may have a different way of doing it hence my post.
Alternative approach (using implicit differentiation);
##\dfrac{x}{y}=t##
on substituting on ##y=t^2##
we get,
##y^3-x^2=0##
##3y^2\dfrac{dy}{dx}-2x=0##
##\dfrac{dy}{dx}=\dfrac{2x}{3y^2}##...
Hi,
I’m interested to understand some of the mechanics involved in meteorites that originate from the asteroid belt. I have researched several including the Barringer and the one in Northern Canada in 2008 that was caught on multiple CCTV cameras. They all have very similar velocities before...
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The book states the following.
Suppose we wish to minimize a function...
In many standard texts the behavior of Foucault’s pendulum is solved by adding the Coriolis force term to equation of motion and deriving two coupled differential equations. Here’s an alternative approach:
4 assumptions are made:
Mathematical pendulum (point mass attached to massless rigid...
Dear mathematicians,
I am getting stuck solving this equation for "d". And what (free)software would you recommend to check this equation?
Thanks a lot!
I am not sure why criss-cross approach would work here, but it seems to get the answer. What would be the reason why we could use this approach?
$$\frac {z-1} {z+1} = ni$$
$$\implies \frac {z-1} {z+1} = \frac {ni} {1}$$
$$\implies {(z-1)} \times 1= {ni} \times {(z+1)}$$
I wonder if the following makes sense.
Suppose we want to multiply ##\int_0^\infty e^x dx\cdot\int_0^\infty e^x dx##.
The partial sums of these improper integrals are ##\int_0^x e^x dx=e^x-1##.
Now we multiply the germs at infinity of these partial sums: ##(e^x-1)(e^x-1)=-2 e^x+e^{2 x}+1##...
https://www.feynmanlectures.caltech.edu/I_10.html
https://www.feynmanlectures.caltech.edu/I_09.html
Using Mathematical approach we can describe the motion of a falling body whose gravity is 32 m/s^2. Analysis shows that this is simply ##s-s_0=ut+1/2at^2##. Similarly we can describe the motion of...
I have read about several approcahes to bypass some classical restrictions to quantum facts such as the electron being in a torus-like shape to avoid ,the greater than speed of light, rotation paradox . Could you recommend websites , sources or books that give good classical analogy to quantum...
Summary: New black hole simulations that incorporate quantum gravity indicate that when a black hole dies, it produces a gravitational shock wave that radiates information, a finding that could solve the information paradox.
Hello, Please excuse the rather "conversational" approach I'm using...
Lim x->c f(x)=L means that for a given ϵ we can find a δ such that when |x-c|<δ-> |f(x)-L|<ϵ. To satisfy the criterion m<f(x)<M we choose ϵ=min (L-m, M-L) and for that ϵ we determine a δ.
m<f(x)<M
m-L<f(x)-L<M-L
|m-L|<|f(x)-L|<|M-L|
|L-m|<|f(x)-L|<|M-L|
|L-m|<|L|+|m|
|f(x)-L|<|f(x)|+|L|...
Givens:
Vyi=12.5 m/s
Vyf=-12.5 m/s (at the same horizontal level)
ay=-9.81 m/s^2
Δy= zero m (as the displacement on the y-axis, when the projectile reaches the same horizontal level, is zero m)
Δt=?
When I use
Δy=[(vyi+vyf)/2]*Δt
I get the time as undefined.
Δt= 2Δy/(vyi+vyf)
= 2*0 m/(12.5...
I am refreshing on the pde's, and i am trying to understand how the textbook was addressing change of variables, i find it a bit confusing. I will share the textbook approach, then later share my own understanding on change of variables approach. Here is the textbook approach;
My approach on...
Homework Statement:: R1 = 2kOHms; R2 = 2kOHms; R3 = 3kOHms;
R4 = 3kOHms; VS = 25V; IS = 10mA
[5,5] a) Determine the power
provided by the source dependent on
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[3.0] b) What is the value of electrical power
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Relevant...
Hi all,
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With my analytical calculation I found a...
In the following review paper on scattering amplitudes, by Elvang and Huang:
https://arxiv.org/abs/1308.1697
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Huygens principle has been extended with two independent efforts in order to reform its original feature that gives rise to a back propagating wave.
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(55x + 45y) = 520 (1)
(45x + 55y) = 480 (2)
So first I notice they are divisible by 5 so I go ahead and do that.
(11x + 9y) = 104 (1)
(9x + 11y) = 96 (2)
11 times 9 is 99 and 9 times 11 is 99 so I can cancel some terms. I proceed to do that by multiplying the top by 11 and getting: (121x +...
There is a beautiful demonstration, available in the text Robert S. Elliot, Antenna theory and Design, Wiley-IEEE Press, page 17 (Stratton-Chu solution), which shows how the electromagnetic field at each point ## \mathbf { r} ## of a volume ## V ##, with boundary ## S_1, ..., S_N ##:
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from problem I find \[ r = r_0 + At \] \[ x_0 = 3 + 2t\] \[ y_0 = -1 - 2t\] \[ z_0 = 1 + t\] and \[ A = (2,-2,1)\]
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