In analytic geometry, an asymptote () of a curve is a line such that the distance between the curve and the line approaches zero as one or both of the x or y coordinates tends to infinity. In projective geometry and related contexts, an asymptote of a curve is a line which is tangent to the curve at a point at infinity.The word asymptote is derived from the Greek ἀσύμπτωτος (asumptōtos) which means "not falling together", from ἀ priv. + σύν "together" + πτωτ-ός "fallen". The term was introduced by Apollonius of Perga in his work on conic sections, but in contrast to its modern meaning, he used it to mean any line that does not intersect the given curve.There are three kinds of asymptotes: horizontal, vertical and oblique. For curves given by the graph of a function y = ƒ(x), horizontal asymptotes are horizontal lines that the graph of the function approaches as x tends to +∞ or −∞. Vertical asymptotes are vertical lines near which the function grows without bound. An oblique asymptote has a slope that is non-zero but finite, such that the graph of the function approaches it as x tends to +∞ or −∞.
More generally, one curve is a curvilinear asymptote of another (as opposed to a linear asymptote) if the distance between the two curves tends to zero as they tend to infinity, although the term asymptote by itself is usually reserved for linear asymptotes.
Asymptotes convey information about the behavior of curves in the large, and determining the asymptotes of a function is an important step in sketching its graph. The study of asymptotes of functions, construed in a broad sense, forms a part of the subject of asymptotic analysis.
Homework Statement
Find the horizontal asymptote to the graph: f(x) = 2x2/(x4-81)1/2
Homework Equations
How do I factor the bottom? Because for, the HA, I compare the coefficients.
I'm a calc newb, and I am a little stumped here. Thanks for your help. How do you do this?
http://www.webassign.net/www29/symImages/0/8/103b04681b693242466ef17cefccc1.gif
Homework Statement
What is an equation for the hyperbola with vertices (3,0) and (-3,0) and asymptote y=7/3x?
Homework Equations
The Attempt at a Solution
I solved this problem but still have a question. The answer is 49x^2-49y^2=441 (I solved it by graphing). However, my...
Hey guys I am not being able to understand the Asymptote. Please say me wheather an Asymptote is a line that really meets the curve or not. If it meets its defination is not saying so beacuse its defination is like this "An asymptopte is a line whose perpendicular distance from any point on the...
Homework Statement
Sketch the graph of (x-1)/(1-x^2).
Homework Equations
Vertical Asymptotes are found in the denominator.
The Attempt at a Solution
I have all I need to sketch this graph except the vertical asymptote. The 1-x^2 is throwing me off. I thought it would come...
Sorry to be a bother at this time around. I have a question though about a weird looking function : e^(6-2x) + 5. (The 5 is outside of the parenthesis, so it is a coefficient, not an exponent). I am interested in seeing how to use limits to construct its graph. In particular, I want to find out...
Which of the following has y=-1 as an asymptote?
1.e^(-x)
2.sin(x)
3.ln x
4.x/(x+1)
5.(3-2x^2)/(2x^2-13x+7)
I've graphed each one on my calculator and I think that 1 is the answer, but it seems that it has y=0 as its asymptote rather than y=-1.
Hi.
I'd like to show that sqrt(x*(x-1)) has the asymptote x-0.5. The coefficient on "x" is found by saying
\lim_{x\rightarrow\infty}\frac{\sqrt{x(x-1)}}{x}=1
but how does one find the 0.5 constant?
Homework Statement
I don't particularly need help with anyone problem, I just need a refresher on how to find the Key Point and Asymptote of an equation like the following:
f(x)=2^(x+2)+3
Y-Int=?
Key Point=?
Asymptote=?
Homework Equations
I'm pretty sure I'll only need the...
I am trying to draw the graph of
y = x + \sqrt{|x|}
Can I say that as x approaches infinity, y approaches x? That would mean that the function has an oblique asymptote at the line y=x but I'm not sure.
Thanks for any help!
scatter plot needs a regression? or line best fitting it.
so far y=3/((x-3.75)/2.75)+9 is a pretty good fit
graph is attached
any suggestions on how to get rid of everything left of the asymptote?
keep in mind:
1. 100 years ago, there were only about 1 billion people on earth, today, nearly 7 billion, whether civilization began 20000 years ago or 200 billion years ago.
2. the advancement of technology today relative to 2000 years ago.
3. wars, deaths etc... have increased...
Alright, I know how to find the horizontal asymptotes
but the vertical asymptotes?
I tried dividing the polynomials but maybe I am not doing it correctly because I cannot get a normal answer...
and I am unsure how to factor the denominator.
1. Homework Statement
find the rational function with the slant asymptote of y = 2x + 1
2. The attempt at a solution
(2x +1) + [u]something over something
The thing I have noticed is that parabola's angle from the x-axis keeps increasing...meaning the object is decreasing from that direction...if that is the case, then how does it go on in that direction forever even though, its speed going in that direction keeps decreasing?
At what rate...
its asking me to find the value of p so that the function won't have a vertical asymptote:
g(x) = (3x + p) / (x^3 + 8)
however, I'm not sure how to figure that out...any help?
Homework Statement
\frac{2x-3}{x-1} find the asymptotes of this equation.
The Attempt at a Solution
We already know that x=1 is a vertical asymptote from calculating the domain.
the denominator of x-1=0 when x=1.
However I'm not sure what it is they mean when later they go onto say...
I use Winshell for writing my tex files, I was wondering if there is any way to set it up to compile my files for asymptote as well.
I just started learning to use asymptote, and was trying to get it working so I could do it all in one editor. Any help would be great. Thanks
Question: Find the Vertical Asymptote if any
f(x)=[tex}\frac{2x}{\sin2x}[\tex]
Im somewhat lost, I cross multi and get 1/2 although my friends tell me this just equals 1. Any ideas?
err...cant get the cool math symbol things to work...
Find the vertical asymptotes of the graph of F(x) = (3 - x) / (x^2 - 16)
ok if i factor the denominator.. i find the vertical asymptotes to be x = 4, x = -4.
The 2nd part of the problem asks:
Describe the behavior of f(x) to the left and right of each vertical asymptote.. I'm not sure...
f(x)=(9x^2-36)/(x^2-9)
I forgot how to get the hotizontal asymptote. Is it f(x)=0?
When I do that, there is no way to solve it
Also, how do I find the intervals for when f is increasing?
I'm not asking for the answer, but the equation, I totally forgot
thanks
Well I'm going through an introductory calculus book and right now I'm on the section of horizontal asymptotes.
Currently I'm stubbed on this:
y = (x^2 - 1) / (x^2 + 1)
I take the limit of the function as x increases or decreases without bound and come up with y = 1 being the horizontal...
Help!
My problem asks to find the vertical asymptotes of x^3/(x^2+3x-10)
I found –5 & 2 to be vertical asymptotes but what I can’t figure out is
how as x->-5- = -oo and x->-5+ = +oo
I have calculated lim x->-5+ x^3/(x^2+3x-10) = -125/(0)(-5 - -2) = -125/-0 = +oo...