The Clausius–Clapeyron relation, named after Rudolf Clausius and Benoît Paul Émile Clapeyron, is a way of characterizing a discontinuous phase transition between two phases of matter of a single constituent. The relevance to climatology is that the water-holding capacity of the atmosphere increases by about 7% for every 1 °C (1.8 °F) rise in temperature.
I would like to calculate the entropy or enthalpies (steam, specific and inner energy) using the SRK [suave-redlich-kwong] equation, the Wilson approximation and (if necessary) the Antoine equation. and the Clausius-Clapeyron equation for a mixture of 0.199 mol/l nitrogen and 0.811 mol/l carbon...
Hey, I have a question about the meaning of a variable in the Clausius-Clapeyron formula.
My textbook (Daniel v. Schroeder) says that the Clausius-Clapeyron formula is (for phase boundary between liquid and gas)
\frac{dP}{dT} = \frac{L}{T\left(V_{g} - V_{l} \right)} .
What is V_{l} or V_{g}...
In working out the Clausius-Clapeyron equation in an elementary method, we usually consider the work done in a Carnot cycle, built with two isothermobarics at ##p## , ##T## and ##p- dp##,##T-dT## pressures and temperatures and two adiabatics, as ##\mathcal{L} = dp(V_g - V_\ell)##, where ##V_g##...
Before this question, the questions were about the Clapeyron equation, and how to estimate ##\Delta s##. I'm completely put off by this question however, and don't know where to start.
I've found that the triple point of water is at ##0.01°C##, and there is indeed data in the table for...
The Clausius-Clapeyron formula is given by
\frac{d P}{d T} = \frac{L}{T \Delta V}
where P and T are the pressure and temperature at the boiling point, respectively, and L is the latent heat per mole at the boiling point, and \Delta V is the change in the volume per mole between the gas and...
Someone who can explain me what approximations there is behind the Clausius-Clapeyron equation or know a good webside where i can read about it.
thanks in advance
Hi first post so forgive any break in widely accepted conduct,
Currently involved in a physics competition one of the question is to investigate geysers. Time and time again I have stumbled upon reference to Clausius-Clapeyron relation. Probably the best source I have come across is a youtube...
Homework Statement
Part (b): Find the temperature in which the pressure is twice the atmospheric pressure.
Homework Equations
The Attempt at a Solution
I've done every part except part (b).
Part (b)
\Delta v \approx v_{gas} = \frac{RT}{p m'}
Therefore the clausis-clapeyron equation...
Homework Statement
Using the Clausius-Clapeyron equation, determine the slope of dp/dT for water-ice I equilibrium and explain why you can skate on ice but not on solid argon.
Homework Equations
Clausius-Clapeyron equation
The Attempt at a Solution
I know what the...
Homework Statement
Use the Clausius-Clapeyron equation and \DeltaHsub = \DeltaHfus +\DeltaHvap at the triple point to show that the slope of solid-gas P-T coexistence curve is greater than the slope of the liquid-gas coexistence curve.
Homework Equations
Clausius-Clapeyron: 1/P...
I know that the relationship between pressure and temperature for an ideal gas is linear. The relationship between vapor pressure and temperature for a liquid, however, is exponential. To make it linear we take the natural log and end up with: \ln P = -\frac{\Delta H_{vap}}{RT} + b . How did we...
Hi everyone!
I'm searching for the constants in Clausius-Clapeyron equation
lnP=A-C/T
I'ld like to know the value of A and C. (for Pressure unity is hPa and Temperature is K )
Thanks
The Clausius-Clapeyron equation is given by:
\frac{dP}{dT}=\frac{LJ}{T(V_2-V_1)}
dP is the change in pressure
dT is the change in temperature
L is the Latent heat of fusion/vaporisation
T absolute temperature of substance
V_2-V_1 is the change in volume
J is heat constant
What is...
1. Acetone has normal boiling point of 56.5 oC, and heat of vaporization of 32.0 kJ/mol. Find the boiling point at 580 mmHg.
2. Given element, its structure and density, find its atomic radius in pm. Cr, body centered cubic, 7.19 g/mL.
Well, as for question 1, I'm totally stumped...