Clausius-clapeyron Definition and 15 Threads

$$\Delta G_{vap}=G(g,P)-G(l,P)\tag{3}$$ $$=G^\circ+RT\ln{\left ( \frac{P}{P^\circ }\right )}-G(l,P)\tag{4}$$ The Gibbs free energy of a liquid is almost independent of pressure, so we use the approximation that ##G(l,P)\approx G(l,P^\circ)=G^\circ(l)##. Then $$\Delta...

I would like to calculate the entropy or enthalpies (steam, specific and inner energy) using the SRK [suave-redlich-kwong] equation, the Wilson approximation and (if necessary) the Antoine equation. and the Clausius-Clapeyron equation for a mixture of 0.199 mol/l nitrogen and 0.811 mol/l carbon...

Hey, I have a question about the meaning of a variable in the Clausius-Clapeyron formula. My textbook (Daniel v. Schroeder) says that the Clausius-Clapeyron formula is (for phase boundary between liquid and gas) \frac{dP}{dT} = \frac{L}{T\left(V_{g} - V_{l} \right)} . What is V_{l} or V_{g}...

In working out the Clausius-Clapeyron equation in an elementary method, we usually consider the work done in a Carnot cycle, built with two isothermobarics at ##p## , ##T## and ##p- dp##,##T-dT## pressures and temperatures and two adiabatics, as ##\mathcal{L} = dp(V_g - V_\ell)##, where ##V_g##...

Before this question, the questions were about the Clapeyron equation, and how to estimate ##\Delta s##. I'm completely put off by this question however, and don't know where to start. I've found that the triple point of water is at ##0.01°C##, and there is indeed data in the table for...

The Clausius-Clapeyron formula is given by \frac{d P}{d T} = \frac{L}{T \Delta V} where P and T are the pressure and temperature at the boiling point, respectively, and L is the latent heat per mole at the boiling point, and \Delta V is the change in the volume per mole between the gas and...

Someone who can explain me what approximations there is behind the Clausius-Clapeyron equation or know a good webside where i can read about it. thanks in advance

Hi first post so forgive any break in widely accepted conduct, Currently involved in a physics competition one of the question is to investigate geysers. Time and time again I have stumbled upon reference to Clausius-Clapeyron relation. Probably the best source I have come across is a youtube...

Homework Statement Part (b): Find the temperature in which the pressure is twice the atmospheric pressure. Homework Equations The Attempt at a Solution I've done every part except part (b). Part (b) \Delta v \approx v_{gas} = \frac{RT}{p m'} Therefore the clausis-clapeyron equation...

Homework Statement Using the Clausius-Clapeyron equation, determine the slope of dp/dT for water-ice I equilibrium and explain why you can skate on ice but not on solid argon. Homework Equations Clausius-Clapeyron equation The Attempt at a Solution I know what the...

Homework Statement Use the Clausius-Clapeyron equation and
\DeltaHsub =
\DeltaHfus +
\DeltaHvap at the triple point to show that the slope of solid-gas P-T coexistence curve is greater than the slope of the liquid-gas coexistence curve. Homework Equations Clausius-Clapeyron: 1/P...

I know that the relationship between pressure and temperature for an ideal gas is linear. The relationship between vapor pressure and temperature for a liquid, however, is exponential. To make it linear we take the natural log and end up with: \ln P = -\frac{\Delta H_{vap}}{RT} + b . How did we...

Hi everyone! I'm searching for the constants in Clausius-Clapeyron equation lnP=A-C/T I'ld like to know the value of A and C. (for Pressure unity is hPa and Temperature is K ) Thanks

The Clausius-Clapeyron equation is given by: \frac{dP}{dT}=\frac{LJ}{T(V_2-V_1)} dP is the change in pressure dT is the change in temperature L is the Latent heat of fusion/vaporisation T absolute temperature of substance V_2-V_1 is the change in volume J is heat constant What is...

1. Acetone has normal boiling point of 56.5 oC, and heat of vaporization of 32.0 kJ/mol. Find the boiling point at 580 mmHg. 2. Given element, its structure and density, find its atomic radius in pm. Cr, body centered cubic, 7.19 g/mL. Well, as for question 1, I'm totally stumped...