Collision Definition and 1000 Threads

In physics, a collision is any event in which two or more bodies exert forces on each other in a relatively short time. Although the most common use of the word collision refers to incidents in which two or more objects collide with great force, the scientific use of the term implies nothing about the magnitude of the force.
Some examples of physical interactions that scientists would consider collisions are the following:

When an insect lands on a plant's leaf, its legs are said to collide with the leaf.
When a cat strides across a lawn, each contact that its paws make with the ground is considered a collision, as well as each brush of its fur against a blade of grass.
When a boxer throws a punch, their fist is said to collide with the opponent's body.
When an astronomical object merges with a black hole, they are considered to collide.Some colloquial uses of the word collision are the following:

A traffic collision involves at least one automobile.
A mid-air collision occurs between airplanes.
A ship collision accurately involves at least two moving maritime vessels hitting each other; the related term, allision, describes when a moving ship strikes a stationary object (often, but not always, another ship).
In physics, collisions can be classified by the change in the total kinetic energy of the system before and after the collision:

If most or all of the total kinetic energy is lost (dissipated as heat, sound, etc. or absorbed by the objects themselves), the collision is said to be inelastic; such collisions involve objects coming to a full stop. An example of such a collision is a car crash, as cars crumple inward when crashing, rather than bouncing off of each other. This is by design, for the safety of the occupants and bystanders should a crash occur - the frame of the car absorbs the energy of the crash instead.
If most of the kinetic energy is conserved (i.e. the objects continue moving afterwards), the collision is said to be elastic. An example of this is a baseball bat hitting a baseball - the kinetic energy of the bat is transferred to the ball, greatly increasing the ball's velocity. The sound of the bat hitting the ball represents the loss of energy.
And if all of the total kinetic energy is conserved (i.e. no energy is released as sound, heat, etc.), the collision is said to be perfectly elastic. Such a system is an idealization and cannot occur in reality, due to the second law of thermodynamics.

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  1. DaveC426913

    I Galaxy collision separates dark matter from regular matter

    "... the gas between the galaxies collided, becoming turbulent and superheated. While both dark and normal matter are influenced by gravity, the normal matter also interacts via electromagnetism, which slowed it down during the collision. Consequently, the dark matter moved ahead, decoupling...
  2. Heisenberg7

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  3. A

    B Is this an Unavoidable Collision between 2 spaceships traveling at 0.6c each?

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  4. I_Try_Math

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  5. I_Try_Math

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    So far I've got: ##p_{1,i} + p_{2,i} = p_{1,f} + p_{2,f}## ##p_{1,i} + 0 = p_{1,f} + p_{2,f}## ##m_1v_{1,i} = m_1v_{1,f} + m_2v_{2,f}## According to the textbook, the final speeds should be written in terms of ##v_{1,i}, m_1, and m_2##. It looks like I need another way to relate everything...
  6. T

    Impulse and perfectly inelastic collision between 2 points

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  7. rocketwaveuk

    I Matter Anti-Matter Annihilation

    The pure energy coming from a collision and how is it measured or is it just "A Formula" and is any of that energy Dark Energy or even Dark Matter, the reason for the question is because the Dark Energy/Matter vs normal Energy/Matter seems to align with what is seen now after the Big Bang...
  8. Bling Fizikst

    Speed of charged balls after collision

    I tried to apply energy conservation . $$\frac{-kQq}{l}=\frac{m}{2}(v_1^2+v_2^2)-\frac{kqQ}{2r}$$ Now conserving momentum : $$0=mv_1-mv_2$$ Solving for ##v_1=v_2=v'## we get : $$v'=\sqrt{\frac{kQq}{m}\left(\frac{l-2r}{2r}\right)}$$ Since the balls are elastic , so they should collide...
  9. I

    B How to determine applied force when two objects collide? (basic physics engine)

    I'm trying to make a very basic physics engine. So far I've got a variety of small things worked out but I've been driving myself crazy trying to work out collisions. From one sense I get I can use momentum and impulse to determine the velocity of an object after a fully elastic collision (no...
  10. S

    B Electron's movement after getting hit by a photon that bounces at 90 degrees

    I just started studying Quantum physics and i'm learning about Comptonspreading and I have this question in my book that I don't completely understand So if an electron is standing still, then it gets hit by a photon moving in a straight line into the electron. The photon then bounces off the...
  11. billtodd

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    I know that the speed of the centre of mass is ##v_{cm}=(mv_0+mv_0)/(2m)=v_0##. But I don't know how to proceed from here with the angular speed around the centre of mass of the system. Any help will be appreciated.
  12. P

    When does Phobos collide with Mars?

    I tried to calculate it, but I think I'm going wrong way. I found m^2/s^2 in the definite integral... (170539114.487m^2/s^2) I don't know what it means!!
  13. S

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    I am stuck with this problem. Intuition tells me the answer is no, but I am struggling to prove it. If we consider two particles travelling in the same direction, the 2nd particle will gain velocity (impulse is in same direction to velocity), and the first particle will lose velocity (if it...
  14. S

    Fast and Furious Scene Analysis

    The collision seems to be an inelastic collision meaning momentum is conserved however, energy is not due to likely thermal energy from the collision. Using conservation of momentum, we can maybe somehow find the initial momentum of each vehicle and set it equal to the final momentums? However...
  15. R

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  16. brotherbobby

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  17. BikGer2

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    Hi, I assumed I was supposed to find the amount of kinetic energy body 2 receives after contact, assuming the collision is central, body 1 will be at rest after the collision. I started by using the equation for conservation of momentum: \begin{align} m_1v_1 = m_1v_1' + m_2v_2' \\ 50 * 20 =...
  18. D

    Why can't satellites be equipped with radar systems so that they can detect (and then avoid) impending collisions?

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  19. B

    Dead simple physics question (still a puzzle to me)

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  20. A

    What was the mistake in solving for the speeds of two marbles after a collision?

    Solved equation 1 for v1f and then substituted into equation 2 and solved for v2f. Got 2.22 as the answer, but it said the answer is incorrect.
  21. Rayan

    I Neutrino-Atom Elastic Scattering: Insights from Particle Physics

    What happens generally when a neutrino/anti-neutrino collides with a light vs heavy atom? My guess is, since neutrinos have very low cross section, their interaction is weak and therefore it will be an elastic scattering! For example: $$ \overline{\nu} + He^3 \rightarrow \overline{\nu} + He^3...
  22. S

    I Does being surrounded by water affect collisions between 2 bodies?

    Imagine there is a square plate fixed at the edge on all sides, it is impacted by a body with a pre-determined kinetic energy. Now assume that this plate is submerged in water and impacted by an identical body with the same amount of kinetic energy. Will the results be different? How to...
  23. Hak

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  24. A

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  25. M

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  26. P

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  27. D

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  28. D

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    Hi everyone I'd like to detect collisions between a circle and a floor. I have set them up as follows: The script runs fine (it's just a circle falling towards the floor), but nothing happens when the two objects collide. Does anyone know what I've done wrong?Thanks
  29. hagopbul

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    Hello all: Watching few news , titanic came and we start to have a question , can I prove that titanic was sunk because of hitting an ice mountain, and not because of torpedo, should we use material specifications , speed of the ship , and material specifications of the ice mountain or we...
  30. A

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  31. KataruZ98

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  32. milkism

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  33. Zalokin

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  34. J

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  35. brotherbobby

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  36. Darmstadtium

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  37. C

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  38. Like Tony Stark

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  39. A

    Question about the solution to this elastic collision

    I found that 1/2m1v1i^2+1/2m2v2i^2=1/2m1v1f^2+1/2m2v2f^2 =>0.5*200*55^2+0.5*46*0^2=0.5*40^2*200+0.5*46*0*vf^2=>vf=78.713 m/s. The true answer is 65.2 m/s and is solved using m1v1i+mvv2i=m1v1f+m2v2f. Are these equations not interchangeable? Why can I not use the equation I used?
  40. A

    Question about two elastic collision formulas

    Equation 1 is equating the kinetic energies of the objects before and after the elastic collision. Equation 2 is equating the momentums of the objects after the elastic collision. They can be used interchangeably as long as the collision is elastic. Am I right in my conclusion?
  41. A

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  42. V

    B Collision time interval of a gas molecule with wall of container

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  43. M

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  44. M

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  45. M

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  46. M

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  47. C

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  48. haha0p1

    How to find resulting velocity in a perfectly elastic collision?

    Using principle of conservation of momentum: m×u=m×v1 + M×v2 Where m=mass of moving particle in the beginning u=Initial velocity of particle m v1= final velocity of particle m v2=velocity of object M m×u-(mv1)=Mv2 (mu-mv1)÷M=v2 My answer is this (mu-mv1)÷M However, it is nowhere close to...
  49. L

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  50. susan_khan

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