Oscillation is the repetitive variation, typically in time, of some measure about a central value (often a point of equilibrium) or between two or more different states. The term vibration is precisely used to describe mechanical oscillation. Familiar examples of oscillation include a swinging pendulum and alternating current.
Oscillations occur not only in mechanical systems but also in dynamic systems in virtually every area of science: for example the beating of the human heart (for circulation), business cycles in economics, predator–prey population cycles in ecology, geothermal geysers in geology, vibration of strings in guitar and other string instruments, periodic firing of nerve cells in the brain, and the periodic swelling of Cepheid variable stars in astronomy.
For the record, here is the lecture I am speaking of.
Consider a double pendulum.
I'm going to skip the setup of the problem and jump to the system of differential equations
$$m\ddot{x}_1=-\frac{3g}{l}x_1+\frac{g}{l}x_2\tag{1}$$
$$m\ddot{x}_2=\frac{g}{l}x_1-\frac{g}{l}x_2\tag{2}$$
where...
Here is the actual lecture.
The equations of motion for ##m_1## are
$$m_1\ddot{x}_1=-T_1\sin{\theta_1}+k(x_2-x_1)\tag{1}$$
$$m_1\ddot{y}_1=T_1\cos{\theta_1}-m_1g\tag{2}$$
The lecture says that we are using small angle approximations
$$\sin{\theta_1}\approx\theta_1\tag{3}$$...
The masses are ##m_1## and ##m_2##.
We measure the displacements of each mass as follows
When the blocks move horizontally, they will move vertically as well, because the length of the pendulums remains fixed. Because vertical displacement is second order in the ##x_j##'s,
$$y_j\approx...
Idea:
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I got...
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I know there's are 2 normal modes because the system has 2 mass. I did the Newton's law for both mass.
##m\ddot x_1 = -\frac{mgx_1}{l} -k(x_1 - x_2)## (1)
##m\ddot x_2 = -\frac{mgx_2}{l} +k(x_1 - x_2)## (2)
In the pendulum mode ##x_1 = x_2## and in the breathing mode ##x_1 = -x_2##
I get...
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I have been trying to figure this out for a long time and don't know what to do after writing
mx''¨(t)=−kx(t)+mg
I figure that the frequency ω=√(k/m) since the mg term is constant and the kx term is the only term that changes.
I...
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Writing out the coupled equations:
$$...
Homework Statement
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Just click the link, The image is huge, so I did not use IMG tags.
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Hi, this is a fairly basic part of the whole coupled oscillators area, but I don't really get it.
My problem is with the equations of motion of a coupled oscillator:
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and
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Everywhere I've read seems to take it as intuitive, but I don't see...
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moved to Advanced Physics Section seemed more relevant
link to it is https://www.physicsforums.com/showthread.php?p=2169513#post2169513"
Sorry for the double post in two spots if this can be removed Thanks Heeps
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http://img356.imageshack.us/img356/28/coupledlagr4fx.png
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