Double slit diffraction Definition and 22 Threads

Given that [y][/m] is equal to the position of the interference maxima and is the variable I’m solving for. I got as far as setting up two expressions, one for sinθ and the other for tanθ. sinθ = (mλ)/d tanθ = ym/L My first instinct was to set θ = 40 degrees. By relating sinθ and tanθ to each...

Hi, I'm doing a very simple problem, but I don't understand the diagram provided (see image below). What is m here? I know that m is the order with respect to the central bright fringe, but there isn't a central bright fringe (assuming those circles are the bright fringes)? Homework...

When observing interference patterns, one will notice that the maxima from a double slit are more intense and farther apart than the maxima of a single slit. Likewise, the maxima from a diffraction grating are more intense and farther apart than maxima of a double slit. Why is this? I...

Homework Statement Laser light of wavelength 517 nm illuminates two identical slits, producing an interference pattern on a screen 87.5 cm from the slits. The bright bands are 1.15 cm apart, and the third bright bands on either side of the central maximum are missing in the pattern. a.) Find...

Consider diffraction in a ripple tank from two narrow slits. Answer true (T) or false (F) for each of the following statements. E.g., if the first statement is true and the rest false, enter TFFF. You have 6 tries. If the frequency of the wave source is halved, then the angle between the...

I'm not quite sure how to describe this phenomena but in my town we have a large boardwalk structure and it is closed off almost entirely underneath by a sea wall. this leaves slits on top with the boards and slits near the top of the sea wall where a concrete beam will pass through. at certain...

Hey guys the Idea of simulating the DSE with a program caught my interest but I just had a few questions regarding the DSE Is there a function that models the probability of finding an electron at a certain point ONCE It's BEEN FIRED FROM AN ELECTRON GUN? like an amplitude function squared or...

I had this problem on my exam and I was pretty sure i knew what to do but it couldn't come up with the right answers. I diagrammed the problem and showed the way i tried to solve it in blue. Can someone tell me where i went wrong? Basically i found the length the of the first maximum off the...

In the double slit experiment, when we send out one photon at a time, what does the appearance of minima in our interference pattern mean? When a single photon is fired, I understand (using "understand" very loosely) that the photon will interfere with itself. When this happens, does it still...

Can somebody explain to me what is the difference between double slit diffraction and double slit interference?, to me they are the same thing but my teacher says they have two different meanings, thanks.

Hello. I have been studying interference and diffraction and one doubt has appeared. When you consider the double slit experiment forgeting the effects of diffraction you get the following equation for intensity I^{}=4I_{0}cos^{2}(\frac{πdsin(θ)}{λ}) where d is the distance between the slits...

In a double-slit experiment electrons are sent through a doule slit where an indicator determines the slit each electron went through. These indicators tell the y coordinate to within d/2, where d is the distance between the slits. If this is the case show that the diffraction pattern will be...

I have no idea where to start with these questions. I am pretty sure I have to use these equations 1. theta = tan^-1(x/D) 2. wsintheta = nlambda 3. dsintheta = nlambda Which order m of in the two-slit interference pattern will give the least uncertainty in the slit spacing, d? a) m = 1 b)...

Homework Statement (a) In a double-slit system, what value of d/a causes diffraction to eliminate the third bright side fringe? Homework Equations I(\theta) = I_mcos^2(\beta)(\frac{sin(\alpha)}{\alpha})^2 \beta =\frac{\pi d}{\lambda} sin \theta \alpha = \frac{\pi a}{\lambda} sin \theta...

Homework Statement Light of wavelength 460nm falls on two slits spaced .3 mm apart. What is the required distance from the slit to a screen if the spacing between the first and second dark fringes is to be 4mm?Homework Equations dsin(theta)=(m+1/2)lambda where d = .3mm y=4mm lambda = 460nm...

Is the formula for single slit diffraction Dsin\theta = m\lambda identical to the double slit diffraction besides m being minima rather than maxima? More specifically will m + 1/2 tell me the angles between maxima?

What effect does the distance between the two slits have on the intensity of the maxima?

Homework Statement A parallel beam of mono-chromatic light (500nm) is incident on 2 long narrow slits: slit width is 0.1mm and the distance between slit centres is 0.3mm. a) How many bright fringes cover the central diffraction maximum? Homework Equations Condition for constructive...

Homework Statement Hey guys, I'm working on a problem with a double slit electron diffraction experiment. There is a beam of electrons shooting through two slits onto a screen. When only slit 1 is open, the number of electrons hitting the screen is 25 times the number of electrons hitting...

Homework Statement Coherent light is passed through two narrow slits whose separation is d. The second-order bright fringe in the interference pattern is located at an angle of theta. If electrons are used instead of light, what must the kinetic energy of the electrons be if they are to...

Homework Statement I apologize for the blurriness in my title, I couldn't find anything better to fit within the length limit. The problem I'm stuck with, paraphrased, is to derive the formula for the diffraction pattern of a double slit, as found in the Young experiment, from the Fraunhofer...

In a double-slit experiment it is found that blue light of wavelength 478 nm gives a second-order maximum at a certain location on the screen. What wavelength of visible light would have a minimum at the same location? ----- I have no clue how to approach this problem but looking in the...