evaluation Definition and 2 Threads

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  1. Rfael69

    I Evaluation of the sum 1^m+3^m+5^m+ ....................(2n+1)^{m}

    how can i evaluate the sum $$ 1^m+3^m+5^m+ ....................(2n+1)^{m} $$ for the case of the normal sum $$ 1^m +2^m +........................+n^, $$ for positive 'm' i know they are related to the Bernoulli Polynomials
  2. chwala

    Use binomal theorem to evaluate ##(0.90)^{2.2}##

    My approach, ##(0.90)^{2.2}=(1-0.1)^{2.2}-1+\dfrac{2.2×-0.1}{1!}+\dfrac{1.2 ×2.2×(-0.1)^2}{2!}+\dfrac{0.2×1.2×2.2×(-0.1)^3}{3!}+...## ## =1-0.22+0.0132-0.000088=0.7931## There may be other approach. Insight welcome.
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