I am just confused on how to find the normal force/ FN of the first object. My classmates are saying Fgy is the exact same as Fn but I don’t get why
Fgy= Fg sin theta
Fgy= (20)(9.81) (sin35)
Fgy= 112.5
Fgy = FN
t= v/a
=25.8 m/s / -2.5 m/s^2
=10.1 s
therefore,
d= vi * t + 1/2at^2
= (25.8)(10.1) +1/2(-2.55)(10.1)^2
=131 m
I got the first one right I think, but I don't know how to do b
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