Jnu 2014 Definition and 18 Threads

  1. Pushoam

    Dimension of length using h,G,c

    Homework Statement Homework EquationsThe Attempt at a Solution Dimension of length using h,G,c [h] = [F r] ##[G] =[ \frac { Fr^2}{m^2} ] \\ [\frac { hG}c] = [L] ## So, the answer is option (b). Is this correct?
  2. Pushoam

    Force exerted by a particle in a box on the boundary

    Homework Statement Homework EquationsThe Attempt at a Solution The energy eigen - value of a particle in a box is given by ## E_n = \frac { n^2 h^2}{8mL^2} ## . Now, applying classical mechanics , ## \frac { p^2}{2m} = \frac { n^2 h^2}{8mL^2} ## . ## p \propto \frac { 1} L ## , So...
  3. Pushoam

    Energy needed to remove both electrons from a He atom

    Homework Statement Homework EquationsThe Attempt at a Solution [/B] Both electrons are in 1s orbit. For taking out the second electron, I will have to put slightly more energy than 24.6eV. So, the energy required to remove both electrons should be slightly more than 49.2 eV. So, I...
  4. Pushoam

    De – Broglie wavelength of O_2

    Homework Statement Homework EquationsThe Attempt at a Solution [/B] De – Broglie wavelength of ## O_2 ## molecule is ## \lambda = \frac h p ## Assuming that the speed of molecule is small enough to take non – relativistic calculation, ## \frac {...
  5. Pushoam

    Frequency of a proton moving in a circular orbit

    Homework Statement Homework EquationsThe Attempt at a Solution [/B]Assuming that the relation ## v = \omega r ## is valid in relativistic calculation. As the speed is greater for higher kinetic energy, ## \omega_2 ## is greater. This is shown by only (d). So, I think (d) should...
  6. Pushoam

    Standard deviation of V_x of He gas

    Homework Statement Homework EquationsThe Attempt at a Solution ## \frac 1 2 m<v_x^2> =\frac 1 2 k_BT , \\ \sqrt{ <v_x^2>} = 556~ m/s ## So, I guess that the standard deviation should be less than rms speed. So, the option is (a) ## \left< ax + b \right> = a\left<x\right> + b...
  7. Pushoam

    Output voltage and output current of an Opamp

    Homework Statement Homework EquationsThe Attempt at a Solution Output voltage and output current of an OP-Amp Taking the OP-Amp as an ideal OP-Amp, the voltage at terminal 1 is 0 with respect to ground. The voltage at B is ## V_B = - 0.5 V ## ## i_{in} ## is from A to B. There is...
  8. Pushoam

    What is the relationship between induced emf and induced electric field?

    Homework Statement Homework EquationsThe Attempt at a SolutionThe emf gets induced due to the changing flux. The flux through the rod remains 0. So, there is no induced emf. I don’t know how to calculate induced electric field. But as there is no induced emf, so there is no induced...
  9. Pushoam

    Engineering LCR circuit, calculating R when frequency width is given

    Homework Statement Homework EquationsThe Attempt at a Solution LCR circuit, calculating R when frequency width is given Applying Kirchoff Voltage Loop Law, ## V_A – V_B + V_B - V_C + V_C – V_A = 0 ## ...(2) ## V_A – V_B ## is potential drop across inductor. Since current is flowing...
  10. Pushoam

    B on center of 2 infinite wires with semi - circular end

    Homework Statement Homework EquationsThe Attempt at a SolutionMagnetic field due to both semi - infinite straight wires on P = Magnetic field due to infinite straight wire on P = ## \frac { \mu_0 I } { 2 \pi a } = 2 * 10 ^{-5} ~wb/m^2 ## Magnetic field due to semi – circular wire on...
  11. Pushoam

    Point charge outside a grounded conducting sphere

    Homework Statement Homework EquationsThe Attempt at a Solution Option (a), because the potential is 0 on the surface, and potential due to point charge is positive so there must be negative charge on the surface. Since opposite charges attract each other, there is an attractive force...
  12. Pushoam

    Doppler effect: calculate speed of a moving star

    Homework Statement Homework EquationsThe Attempt at a Solution When the source is not moving, ## \lambda = 6250 A ## ...(1) When the source is moving, ## \lambda ' = 6500 A ## ...(2) From (1) and (2), ## \lambda ' > \lambda ## ...(3) This means that the source is moving away from...
  13. Pushoam

    Dispersion relation for a surface wave of a pool of water

    Homework Statement Homework EquationsThe Attempt at a Solution ## v = \frac { \omega } k ## ## \omega = \sqrt{ kg \tanh (k) } ##I have no idea to guess the graph. I put g = 9.8 and tried to calculate ## \omega ## for different values of k. ## \omega (0 ) = 0, \omega (30) =...
  14. Pushoam

    What is the formula for calculating fringe width in an interference pattern?

    Homework Statement Homework EquationsThe Attempt at a Solution When the system is in air ## d \sin {\theta} = n \lambda ## ...(1) When the system is in water and slit separation is 2d, ## \mu 2d \sin {\theta} = n \lambda ## ...(2) ## \tan {\theta} = \frac y D ## ...( 3)...
  15. Pushoam

    Determinant of exponential matrix

    Homework Statement Homework EquationsThe Attempt at a Solution [/B] Det( ## e^A ## ) = ## e^{(trace A)} ## ## trace(A) = trace( SAS^{-1}) = 0 ## as trace is similiarity invariant. Det( ## e^A ## ) = 1 The answer is option (a). Is this correct? But in the question, it is not...
  16. Pushoam

    Calculating water pressure in a horizontal pipe

    Homework Statement Homework EquationsThe Attempt at a Solution Calculating water pressure using in a horizontal pipe Applying Bernoulli principle, ## p_a + \frac 1 2 \rho gh_a + \frac 1 2 \rho v_a^2 = p_b + \frac 1 2 \rho gh_b + \frac 1 2 \rho v_b^2 ## ## h_a = h_b, v_b = \frac {...
  17. Pushoam

    Change in the potential energy of a star after explosion

    Homework Statement Homework EquationsThe Attempt at a Solution I think : the question means that almost all of the potential energy gets used into the explosion. If this is true then the potential energy gets reduced by ## \frac { GM^2} R ## or if the star just gets transformed into a...
  18. Pushoam

    Ratio of K. E. of solid cylinder to shell

    Homework Statement Homework EquationsThe Attempt at a Solution total kinetic energy of a rigid body = rotational kinetic energy of the body around its center of mass + translational kinetic energy of center of mass For solid cylinder, total kinetic energy = ## \frac { [I = \frac 1 2...
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