TL;DR Summary: Ohms Law Source Voltage DC series Circuit
Hello,
I'm trying to figure out how to determine source voltage of a DC series circuit. The only information given is
Resistor 1 = 12ohm
Resistor 2 = 9ohm
Resistor 3 = 3ohm
And the voltage drop across R1 is 6V.
The answer is 12V...
On Chegg they solve for V using P=V^2/R using 36W and R1= 25Ω, which is equal to 30V
then they add R1+R2 = 40Ω and they plug in P=V^2/R and solve for P which is 22.5W
I'm confused on why they didn't use P=I^2*R cause you know the system is in series so I is the same and solve for I then...
So am trying to find the current in the RLC series circuit ,but i think i have done something wrong ,if anyone could tell me where i went wrong ,it would be great ,thank you
Resistor-100ohms
Capacitor-0.01uF
Inductor-25mH
Voltage Source-50v a.c
1kHz
Hello, this is my working. My professor did not give any answer key, and thus can I check if I approach the question correctly, and also check if my answer is correct at the same time.
for t < 0,
V(0-) = V(0+) = 60V
I(0) = 60 / 50 = 1.2A
When t > 0,
$$α = \frac{R}{2L}$$
$$α =...
I calculated in the following and got the correct answer. However, I wonder whether this way is correct or not. Thanks!
PR / Pavg = Irms^2 * R / Irms^2*Z = 15 /33.36 = 0.45
Attached is the section from the book. I am doing section 31.3
We know that an AC source gives a sinusoidal varying current, and as far as I know its always given by ##i(t) = Icos(wt)##. Its like we take the current to be the base of all other quantities, so we use it to derive everything else...
Known: V source = 30.0 V
, R1 = 15.0 W, R2 = 15.0 W, R3 = 15.0 W
To determine the current, first find the equivalent resistance.
I = Vsource/R and R = RA + RB
= Vsource/RA + RB
30.0 V/15.0 W + 15.0 W + 15.0 W
= 1.5 A
This is as far as I could do the work for this question. I’m having trouble..
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[moderator: moved from a technical forum. No template.]
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