So far I have reached a pretty promising equation that if uk * g >= F/(m1+m2+…+mn) then kth block will atleast surely not slide wrt the lower one. But the converse to this that if uk * g < … then it will “surely” slide is wrong!!
Stuck on this from many days!
Thanks (:
While my hunky husband was lifting the chair up, and my brawny brother pushing the frame down, I kept hitting the top of the slide with a screwdriver, to try to loosen the slide. But these parts are still wedged too tightly! We ran out of energy and ideas! How can we life hack this please...
My textbook derives the condition for bright and dark fringes on an air wedge by assuming that the reflected and refracted rays have a path difference of pi. Hence the conditions for bright and dark fringes end up being the opposite of what is expected.
However I did not really understand the...
I'm a researcher hoping to look at some papers on the technical aspect of water physics on a water slide. Does anyone have resources or pointers for me? Essentially, I'm trying to find the optimal amount of water needed to propel a passenger down a standard straight water slide, but I don't know...
¿Cómo es la calidad de la acción y la variación de la energía y el movimiento, durante el desplazamiento, cuando se usa un columpio y un tobogán de agua?
[Translated by a Mentor using Google Translate]
Good day All!
I have a problem , I could do almost all the mechanism, my problem is how to make slide the little ball into the groove. whenever i run the program i got the follwing error message
['rotating_groove_cylinder_good_trial']: The following errors were found in the model...
ma = mg * sinα - fmg * cosα
a = g (sinα-f * cosα)
v = g*t(sinα - f * cosα)
14.7 = 10 * 2 (sin60 - f * cos60)
f = 0.26
Can someone please check if my solution is correct? I'd really appreciate that.
Digression, but what on Earth is that ruler thing he's using to calculate products at 14:10 and 15:40?
Edit: I found it, it's called a "slide rule":
https://www.math.utah.edu/~alfeld/sliderules/
Vf = ?
y = ?
ME = mgy + 1/2mv^2
ME = 56*9.81*y + 1/2*56*1^2
Ui + Ki = Ui + Ki
gyi + 1/2vi^2 = gyf + 1/2 vf^2gyf = 1/2vf^2
vf = 5.425 m/s
9.81y + 1/2*1^2 = 9.81*1.5 + 1/2*5.425^2
y = 2.949 m
MEi = 56*9.81*2.949 + 1/2*56*1^2
MEi = 1648 J
The picture for this problem really confuses me. I am...
This is a rough sketch of the model.
It is frictionless.
I originally tried simple right-angle trig (sin θ =opp/hyp), but that just ends up as sin θ = sin θ , as well as cos θ = cos θ.
I feel like there's also a way to manipulate dynamic equations around to equate something that is capable...
I don't really understand if the initial horizontal velocity is 0? Or do I assume it's some constant? Putting aside vertical velocity.
Also how should the "mechanical work done by gravity" be calculated? Is it just ##W = \frac{1}{2}mv^2_{final} - \frac{1}{2}mv^2_{initial}##
Hi! Does anyone know what drag coefficient has a person in a water slide? I've only found for full vertical/horizontal body, but not for a person in a water slide, considering it has a slope. Related to that, the cross area of a person can be calculated?
Thanks.
First I found the moment of inertia of the rod + rider to be I = (70 kg * 62 m2+ 1/3 * 24 kg * 62 m2)= 2808
Then I found initial angular momentum of the pole and rider just as the rider grabs the pole:
L = Iw = 2808 v0/ 6 m = 468 v0
Then I found the final angular momentum of the pole and rider...
It still has the guide cards for how to read it for different types of valves, etc... I found it in a small town store, outside Nashville, TN, USA, picked it up because I haven't seen one of these before. A little tedious to use, but, it is more capable than I would've thought. Thought...
Homework Statement
The system is released from rest with no slack in the cable and with the spring stretched 225 mm. Determine the distance s traveled by the 3.2-kg cart before it comes to rest (a) if m approaches zero and (b) if m = 2.5 kg. Assume no mechanical interference and no friction...
I am trying to understand how fluids form particular shapes when put on a solid.
In the two figures,what are we taking as a system for the forces?
How the resultant of the forces influences the shape of the different fluids?
Hello
My question has two parts:
1) Why is plano convex lens used in slide projector? Why can't we use simple convex lens in it?
2) Why are two plano convex lenses used in slide projector? Why can't we use only one?Thanks!
Homework Statement
which one would be faster when reached the ground?
Homework EquationsThe Attempt at a Solution
conservation of energy
Pe=Ke
mgh=1/2mV^2
for 2-)m*g*cosa*(h/cosa)=1/2*m*V^2 -- V= sqrt(2*g*h)
for 1-) V=sqrt(2*g*h)
so V1=V2
How would sliding the plates parallel to each other in order to separate them (they are prevented from contacting to avoid friction) require the same amount of energy as pulling them apart? You're not pushing against the force (the net force at the edges pulling it back is balanced by opposite...
Say you (a skilled motorcycle racer) ride a motorcycle in a big empty parking lot and ride in a big circle of constant radius and slowly go faster and faster. If you are careful as you go faster will you all of a sudden go from very little power slide to a lot of power slide like the video...
Homework Statement
Two blocks slide on an incline of angle \theta . Block 1 has mass m1 and coefficient of kinetic friction μ1 with the surface, block 2 has mass m2 and coefficient of kinetic friction μ2. The gravitational acceleration is g.
In terms of these parameters, under what condition...
Homework Statement
A stiff spring with a spring constant of 1200 N/m is connected to a bar on the slide generator as show in figure P32.40 Assume the bar has length l = 60 x10^-2 m and mass .75 kg, and it slides without friction. The bar connects to a U shaped wire to form a loop that has width...
Homework Statement
13.43 A child slides down the helical water slide AB. The description of motion in cylindrical coordinates is
##R=4m##, ##θ=ω^2t^2## and ##z=h[1-(\frac {ω^2t^2} {π})]##, where h=3m and ω=0.75rad/s.
Compute the magnitudes of the velocity vector and acceleration vector when...
Homework Statement
A sledge of mass m1 is pulled horizontally with a force F. On the sledge there is a body of mass m2 that can slide on the horizontal platform of the sledge with the friction coefficient μ. Another sledge of mass m3 is tied with a horizontal string of the body m2. Between the...
Homework Statement
Students used a speed gun to measure the final speed of slider at the bottom of the slide. They measure the height difference between the top and bottom of the slide to be 3.0 m.
If the speed of a slider at the bottom of the slide is 5.0 m/s, what is the efficiency of the...
1.Question:
A penguin is going down a slide. The coefficient of kinetic friction between the penguin and the slide has a value of 0.77. It takes three times as long to slide down this slide as it would if the slide were frictionless. Find the angle of the slide.
2. My answer: I chose solving it...
Homework Statement
In the figure shown, friction force between the bead and the light string is ##\dfrac{mg}{4}##. Find the time in which the bead looses contact with the string after the system is released from rest.
Homework Equations
Weight of the bead ##(m_1)=mg##
Friction acting on the...
Homework Statement
[/B] A billiard ball of mass m and radius r is being hit and starts to slide
on a surface with equivalent of friction μ.
What is the friction force
The distance to rolling only
What is the energy loss in the sliding phase
Homework Equations
Kinetic energy of a solid body...
Homework Statement
A block is at rest on a ramp on a table with no friction between the surfaces. The ramp has an incline of 30 degrees. The mass of the block is 4kg, and the mass of the wedge is 6kg. What magnitude force can be applied to the opposite side of the ramp such that both the ramp...
Homework Statement
Homework Equations
m*v^2 / 2 and k*x^2 / 2 and 0,5*m*v^2
The Attempt at a Solution
[/B]
in task a I got correct answer there v = 20 m/s
in task b I got wrong answer I got the distance = 0,76 m but I should be 32 m
here is my answer :
0,5*m*(sin(30)*v) - mu * m*g*cos(30)...
I have the following optical setup, in which the goal is to record the diffraction pattern of a sample on an image detector some distance away. In this particular case, the sample is sitting on a standard microscope glass slide.
Now, after recording the diffraction pattern, I numerically...
I have attached a copy of the full question and my diagram which I thought was correct but it does not give me the correct answer. The answer for (i) is that it stays put and for (ii) that it topples.
I do not get = 0 for any of them. I get some values... (i) -0.15 for slide, 0.346 for topple...
1. Homework Statement
Homework Equations
Friction ≤ μR
The Attempt at a Solution :[/B]
Ok so I need help for (ii) and this is what I did:
I thought that in order for A not to slide, the net force on B ≤ Friction between the boxes
450a ≤ 0.2(200g)
a≤0.89
however, when I tried this...
Homework Statement
If m=5.0kg, φ=30◦ and μs =0.87, what is the minimum force needed to make the box slide down the slope?
[/B]
Homework Equations
force of status friction is less than or equal to the normal force multiplied by the coefficient of static friction
F,normal=mgcosφ
The image...
Homework Statement
Find the time it takes for block A to slide 0.5m on block B.
Mass A=10 kg
Mass B=35 kg
I included a screen shot from my online homework.
Homework Equations
FR=FNμkThe Attempt at a Solution
For Block A:
mAa=T-FRA-WAsin(30)
T=10a+68.67
For Block B:
FRC=(mAg+mBg)μBC
FRA=mAgμAB...
Homework Statement
MECHANICS:
Given Theta, L, M, and acceleration of elevator relative to ground. Find the time it takes for the block to reach the end of the incline.
Here is a diagram: http://k-elahian.com/tmp/nip.PNG
Homework Equations
f=ma
kinematics
relative acceleration
The Attempt...
Homework Statement
Homework Equations
ΣFx=max
The Attempt at a Solution
I drew a free body diagram for the box and set up the equation to solve for θ, but I'm not sure how to do it without μ
Hi.
I am re-engineering a 40+ year old carburettor design. The current throttle slide has stress raiser flaws and is the same material as the mixing chamber that it slide interfaces with. The prototype slides were printed in ABS for fitment trials. The functional trials used Acetal allowing for...
Homework Statement
I'm designing a device for changing a load position from vertical to horizontal. It has a wheeled frame (2) which allows an operator to transport the load after reorientation.
The combined centre of gravity of a rotating platform (1) and the load moves forward due to...
Homework Statement
A particle (of mass m) is free to move along a frictionless curve y(x) which is rotating about the y-axis at a constant angular speed ω. A uniform gravitational field (of strength g) acts along the negative y direction. Find the equation of motion of the particle.
(That's...
I would have replied to the older thread but it seems that is not possible, so I will have to post my question here.
https://www.physicsforums.com/threads/slide-rule.245855/
@BobG mentioned being able to solve a particular problem:
exp(x)=x^4
really quickly using a slide rule. He emphasized...
Homework Statement
Pco20- Wsin30-100(9.81)(cos20) –Fs = 0
Pcos20 - 1000x9.81xsin30 – 100x9.81xcos20 – 0.2 x ( Wcos20x9.81 + Psin20 ) = 0
Pcos20 – 4905-921.8-1700-0.07P=0
7526.8= 0.869P
P= 8661N
what's wrong with my working ? the ans given is P=7330N
Homework EquationsThe Attempt at a Solution
Homework Statement
A girl whose weight is 294 N slides down a 6.5 m long playground slide that makes an angle of 20◦ with the horizontal. The coefficient of kinetic friction between the slide and the girl is 0.23.
(a) What is the normal force of the slide acting on the girl?
(b) How much energy...
Greetings all,
I am trying to build a sliding gate operator. I have this wiper motor which says, 24v dc, 64rpm, nominal torque- 4Nm.
Max weight of gate to be 400kg, sliding on a steel rail (Not sure how to consider rolling resistance or Co-eff of friction) . Max pull force to be achieved by...
Homework Statement
How far will a box slide if its initial velocity is 1.5 m/s, kinetic friction is 0.15 and the object is 30 kg
Homework Equations
a= (kinetic friction)(acceleration due to gravity) and
V(final)^2 - V(initial)^2 = 2(a)(D)
The Attempt at a Solution
a= 0.15 x 9.81 m/s^2
=...