My work seems to be wrong somehow since my answer is wrong, and I need your help to find out which part is going wrong for me :/
My work:
1.
2.
3.
4.
5.
6.
(10/7)/(10/7+7) = 0.7627A, which is not the answer.
May I consult where is the problem in solution? THanks
Homework Statement
Find the Thevenin equivalent at terminals a-b
V1 = 70V
V2 (dependent) = 4Vo
R1 = 10Kohm
R2 = 20Kohm
Homework Equations
##V=RI##
##1/req = 1/r1 + 1/r2 + ... +1/rn##
The Attempt at a Solution
Found the current i = 1mA by KVL using Vo = 10ki then did source...
Homework Statement
Homework EquationsThe Attempt at a Solution
I have attempted and completed all questions. However, I am now trying part (b) with transforming the voltage source into a current source. I am unable to work out the current and I am unsure what to do next.
I have included my...
I have one circuit and another with a source transformation figure a and b respectively. My question after transforming the 30 mA source shouldn't the current going into node 5 equal the current going into node 4?
Figura a. Before the transformation of the source
Figure b. After the...
< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >
Hi,
I was working on a the source transformation and i got to the part where there are two current sources in the circuit. The current sources were added together (giving they were going in the...
Homework Statement
I'm asking this question because I was trying to apply the method to a Thevenin Eq problem and the answer came out wrong.
Also one more related question. According to the textbook, when a current source is connected both in series with a resistor and in parallel with...
I'm extreeeeamly rusty at basic circuit theory.
I want to transform a sort of infinite arrangement of this circuit:
The values themselves aren't important, just the representation of what's happening, all the verticle resistors are the same value as each other, and all the horizontal resistors...
Hi.i know that a ideal current source has infinite resistance and it supply's constant current to aload connected across it. The current source doesn't have the infinite resistance in series to it but in pparalle. All is well until I think of this Norton's Therom. When we transform a voltage...
Hey guys, i did this source transformation as an alternate method to find the transfer function of a circuit, however I am getting a different transfer function of 2/(2s+(s+3)(s^2+1)) to the solution in the following image. Any help would be really appreciated :)
It's question 1b) Please view attached
1. Just to clarify, when different voltage sources are in series you pick the smaller one?
2. First step, they turned the 1A and 2ohm into 2V, why does the resistance disappear? Then between the last two steps the 12/7 ohm resistance remains with 18/7...
Homework Statement
I'm to use source transformation to find the current through the 24 Ohm resistor
2. The attempt at a solution
I used source transformation on the left 12V source and got a .5A current upwards. The 24 and 30 ohm resistor are in parallel so I found an equivalent resistance of...
Homework Statement
Image Attached
Homework Equations
Ohm's
The Attempt at a Solution
Combined the two resistors in series : 250 + 550 = 800 kΩ
Source Transformation (Current Source): V = 140,000(2*10^-6)= 0.28 V
Combine the voltage sources : 6 - 0.28 = 5.72 V
But then I...
Homework Statement
Use resistance reduction and source transformation to find Vx in the circuit below. All resistance values are in ohms.
Homework Equations
The Attempt at a Solution
For this problem, I know I can combine the 16 Ω resistors, but where I'm having a little trouble...
Homework Statement
I am a bit confused on why they can just randomly short the 4kΩ resistor, as you can see from the first pic to the second pic.
THanks
Homework Equations
The Attempt at a Solution
Homework Statement
Use source transformation to find the Thevenin equivalent circuit with respect to terminals, a, b.
Homework Equations
Voltage Division: (V in)*(R1/R1+R2)
Thevenin / Norton / source transformation procedures
RTh = RNo
VTh = INo*RNo
Polar...
Homework Statement
http://imageshack.us/a/img26/8403/homeworkprobsg28.jpg a. Use source transformations to find the voltage V0 in the circuit (green).
b. Find the power developed by the 250V voltage source
c. Find the power developed by the 8A current sourceHomework Equations
V = IR
KVL...
Homework Statement
Basically, I'm having trouble doing the source transformation and subsequently finding the norton equivalent for this circuit and I don't really know where to start.
The circuit is attached where:
i=3A
V=90V
Please help!
Hi all ,
is it possible to use the source transformation for dependent source ..?
i guess yes because i came across a problem which asks to use source transformation to find Vx as shown :
http://img571.imageshack.us/img571/2389/50111057.jpg
and my solution was ...
Homework Statement
Find Vx using source transformation
Homework Equations
V=IR
KVL
The Attempt at a Solution
After doing source transformation on the three pairs of current sources and resistors...
KVL:
-6+2I-Vx+4I-3+3I+5I-2=0
14I-Vx-11=0
but Vx=5I (is it? I'm not so sure about this)...
Homework Statement
http://img5.imageshack.us/img5/2959/question2e.jpg Homework Equations
- A current source in parallel with a resistor can be transformed into a voltage source in series with a resistor. R stays the same and Vs = R*Is
The Attempt at a Solution
I have tried it in two ways. Both...
Homework Statement
[PLAIN]http://img706.imageshack.us/img706/5328/prob31.jpg
Homework Equations
v = r * i
The Attempt at a Solution
Having issues with the left box I think. I have been starting on the right side and working left by first starting with the 5A current source...
I'm trying to understand source transformation and with my research, I have had some confusion. I have two question regarding them and would appreciate any help.
I understand that the thevenin resistance is found by short circuiting the voltage source. Is that also the case when you short...
Homework Statement
Use source transformation to find the voltage V_x in the circuit below.
http://img207.imageshack.us/img207/5150/chapter4problem24ij9.jpg
Homework Equations
V_S\,=\,i_S\,R
i_S\,=\,\frac{V_S}{R}
KCL, KVL, v = i R, super-node?
The Attempt at a Solution...