Problem:
Solution part a)
where formula 6.14 is just M x n.
We need to do part b without seperation of variables, I'm quite stuck. Will B just be the magnetic field inside a solenoid? How can I find the other fields.
d(ɣmv)/dt = qvB
(dɣ/dt)mv + ɣm(dv/dt) = qvB
Substituting gamma in and using the chain rule, it ends up simplifying to the following:
ɣ^3*m(dv/dt) = qvB
Now, I am confused on how to solve for v.
My solution was as follows:
$$\frac {d\overrightarrow p} {dt}=q \frac {\overrightarrow v} {c}\times \overrightarrow B_0$$
The movement is in the ##[yz]## plane so ##|\overrightarrow v\times \overrightarrow B_0|=vB_0##, therefore: $$\biggr |\frac {dp} {dt}\biggr |= \frac {qvB_0} {c}.$$ On the...
In NMR, protons that are near each other exchange energy with each other by photon emission and absorption.
Proton A is spin down, and proton B is spin up. proton A emits a photon and becomes spin up, and proton B absorbs this photon and becomes spin down. have the two protons been entangled?
Assume a solenoid coil(made up of ##N## windings) placed in the horizontal(##\hat{y}##) direction and in a constant uniform magnetic field.
Would an induced current run through the(closed) coil if it spins around its central horizontal ##\hat{y}## axis? My guess is "no", since such a current is...
Hi all, I interested in how can I get low of motion in for orbiting particle in a uniform magnetic field
$$\frac{d\vec{r}}{dt} = \vec{\omega}\times\vec{r},\qquad
\vec{\omega} = \frac{e\vec{B}}{mc},$$
Of course, rotating about z' axis is very simple.
\begin{equation}\label{eq:K}...
If ##\tau= 0.0727, N=60, i=1.3, B=1.0,## and ##\theta=15##, I tried the following calculation:
##\tau=NIABsin\theta##
##\tau=NIs^2Bsin\theta##
##s^2=\frac {\tau} {NIBsin\theta}=\frac {.0727} {60*1.3*1*sin(15)}=0.0632 m=6.32 cm##
The answer is probably right in front of me, but I don't know what...
So this was a section taken out from a question which I am trying to do shown below
I have drawn a sketch to help me visualise of what is going on
I have used Fleming's left hand rule to help me determine what direction the force is facing on each side of the coil.
For the last part in...
a) We can solve for acceleration by looking at FNETy
FNETy = FE (G is negligible)
FNETy = m * a
The mass (m) of an electron is 9.1093836 x 10-31 kg.
The elementary charge (q) of an electron is -1.60217662 x 10-19 C
a = ε * q / m
a = (4.0 x 102 N/C * 1.6022 x 10-19 C) / 9.1094 x...
I started with the first of the relevant equations, replacing the p with the operator -iħ∇ and expanding the squared term to yield:
H = (-ħ^2 / 2m)∇^2 + (iqħ/m)A·∇ + (q^2 / 2m)A^2 + qV
But since A = (1/2)B x r
(iqħ/m)A·∇ = (iqħ / 2m)(r x ∇)·B = -(q / 2m)L·B = -(qB_0 / 2m)L_z
and A^2 =...
All i could think is that the z component of velocity will remain unchnged as there is no force in that direction.And for the x and y component can we imagine the helical motion as a superposition of a circle and a straight line.So for x and y component can we solve for a particle moving in a...
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Problem given in the image attached.
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https://dl.dropbox.com/u/63664351/Physics/Electromagnetic%20Induction.PNG
https://dl.dropbox.com/u/63664351/Physics/Electromagnetic%20Induction%20Answers.PNG Homework Equations
W=mas.
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L=\frac{1}{2}mv^{2} + \frac{q}{c}\mathbf{v}\mathbf{.} \mathbf{A}
I've been searching through Griffith's, Jackson, and google to no avail.
Can we start from the lorentz force and work backwards?
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d\hat{S}/dt = γ\hat{S} \times \hat{B}
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