1) A rope 5m is fastened to two hooks 4m apart on a horizontal

In summary, the conversation discusses problems involving ropes, poles, weights, and forces. The first problem involves a rope attached to two hooks on a ceiling and a 10kg mass. The tension in the string is to be computed, given the lengths of the rope segments. The second problem involves a 7m long pole, a boy and a man supporting it, and a 20kg weight that needs to be attached at a certain point for the man to support three times as much weight as the boy. The third problem involves a man carrying a load on a uniform pole and determining the vertical force applied by his hand and the force on his shoulder, using the rule of equilibrium. The conversation also mentions the importance of creating a diagram and
  • #1
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1) A rope 5m is fastened to two hooks 4m apart on a horizontal ceiling. To the rope is attached a 10kg mass so that the segment of the rope are 3.0m and 2.0m.Compute the tension in the string.
2) A uniform pole 7m long weighing 10kg is supported by a boy 2m from one end and a man 3m from the other end. At what point must 20kg weight be attached so that the man would support thrice as much weight as the buy
3)A man carries a load of mass 2.6kg from one end of a uniform pole 100cm which has a mass 0.4kg the pole rests on his shoulder at a point 60cm from the load he holds it at the other hand what vertical force must be applied by his hand and what is the force on his shoulder.

Rule of equilibrium under parallel complanor force
Total downward forces = total upward forces
total anticlockwise moment= total clockwise moment
moment= force x perpendicular distance to line of action.
 
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  • #2


My attempt
 

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  • #3


You have to imagine that you are hanging the mass as directed in the problem. Try to do that and you get the correct diagram.
 
  • #4


OK but what's the formula for computing tension?
 
  • #5


It all starts from the diagram according to the way I know how to do it.
 

FAQ: 1) A rope 5m is fastened to two hooks 4m apart on a horizontal

What is the tension in the rope?

The tension in the rope is dependent on the weight of the object being supported by the rope. It can be calculated using the formula T = mg, where T is the tension, m is the mass of the object, and g is the acceleration due to gravity (approximately 9.8 m/s^2).

How do the angles of the rope affect the tension?

The angles of the rope affect the tension by increasing or decreasing the force needed to support the same weight. As the angles of the rope increase, the tension in the rope also increases. This is due to the increase in the horizontal component of the tension force.

Can the rope support more than one object at once?

It is possible for the rope to support more than one object at once, as long as the combined weight of the objects does not exceed the maximum tension the rope can handle. However, this will also depend on the distribution of weight and angles of the rope.

What happens if one of the hooks breaks?

If one of the hooks breaks, the tension in the rope will be unevenly distributed and the remaining hook will have to support the entire weight of the object. This can potentially cause the remaining hook to break as well.

How does the length of the rope affect the tension?

The length of the rope does not directly affect the tension, as long as it is long enough to reach between the two hooks. However, a longer rope may have a higher maximum tension capacity, making it able to support heavier objects.

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